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Verizon [17]
3 years ago
13

2 pounds of grapes cost $6.36. At that price, how much will Kayden spend on 3 1/2 pounds of grapes.

Mathematics
1 answer:
aliya0001 [1]3 years ago
8 0

Answer:

11.13

Step-by-step explanation:

Let's find the cost of 1 pound of grape. So 6.36 is 2 pounds, so 1 pound must be 6.36/2.

6.36/2 = 3.18

We want 3 and a half pounds of grapes so

3.18 x 3 + 3.18/2 = 9.54 + 1.59 = 11.13

We solved it!

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What is the answer to this?
Dmitry [639]

Answer:

  (c)  III

Step-by-step explanation:

If you simplify the equations and the left side is identical to the right side, then there are an infinite number of solutions: the equation is true for all values of x.

Another way to simplify the equation is to subtract the right side from both sides. If that simplifies to 0 = 0, then there are an infinite number of solutions.

__

<h3>I. </h3>

  2x -6 -6x = 2 -4x . . . . eliminate parentheses

  -4x -6 = -4x +2 . . . . no solutions (no value of x makes this true)

__

<h3>II.</h3>

  x +2 = 15x +10 +2x . . . . eliminate parentheses

  x +2 = 17x +10 . . . . one solution (x=-1/2)

__

<h3>III.</h3>

  4 +6x = 6x +4 . . . . eliminate parentheses

  6x +4 = 6x +4 . . . . infinite solutions

__

<h3>IV.</h3>

  6x +24 = 2x -4 . . . . eliminate parentheses; one solution (x=-7)

8 0
2 years ago
Solve the equations by factoring:<br><br>x^2−3x−40=0<br><br>4x^2−81=0
Alja [10]

Answer:

see explanation

Step-by-step explanation:

Given

x² - 3x - 40 = 0

Consider the factors of the constant term (- 40) which sum to give the coefficient of the x- term (- 3)

The factors are - 8 and + 5, since

- 8 × 5 = - 40 and - 8 + 5 = - 3, thus

(x - 8)(x + 5) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 8 = 0 ⇒ x = 8

x + 5 = 0 ⇒ x = 5

------------------------------------------------------

Given

4x² - 81 = 0 ← this is a difference of squares and factors in general as

a² - b² = (a + b)(a - b), thus

4x² - 81

=(2x)² - 9²

= (2x + 9)(2x - 9) = 0 ← in factored form

Equate each factor to zero and solve for x

2x + 9 = 0 ⇒ 2x = - 9 ⇒ x = - \frac{9}{2}

2x - 9 = 0 ⇒ 2x = 9 ⇒ x = \frac{9}{2}

8 0
3 years ago
Read 2 more answers
A bag contains 5 blue marbles, 6 red marbles, and 9 green marbles. Two marbles are drawn at random, one at a time. What is the p
Leokris [45]
Your answer would be C. 27/190.

This is because the probability of choosing green as the first marble would be 9/20, as there are 20 marbles in total and 9 of those are green.

The probability of choosing a red marble as the second marble would be 6/19, as no red marbles would have been lost if green was picked first, but there would be one less marble in total.

The 'and' rule for probability, the one that is used to determine the probability of P(A) and P(B), is to multiply, so we need to do 9/20 × 6/19 = 54/380 = 27/190.

I hope this helps!
7 0
4 years ago
Solve for x <br> x^2 - 2x - 35 = 0x
olga_2 [115]

Answer:

 x = 7

 x = -5

Step-by-step explanation:

Given

x² - 2x - 35 = 0

Consider the factors of the constant term (- 35) which sum to give the coefficient of the x- term (- 2)

The factors are - 7 and + 5, since

- 7 × 5 = - 35 and - 7 + 5 = - 2, thus

(x - 7)(x + 5) = 0

Equate each factor to zero and solve for x

x + 5 = 0 ⇒ x = - 5

x - 7 = 0 ⇒ x = 7

4 0
3 years ago
The time intervals between successive barges passing a certain point on a busy waterway have an exponential distribution with me
lisov135 [29]

Answer:

a) <u>0.4647</u>

b) <u>24.6 secs</u>

Step-by-step explanation:

Let T be interval between two successive barges

t(t) = λe^λt where t > 0

The mean of the exponential

E(T) = 1/λ

E(T) = 8

1/λ = 8

λ = 1/8

∴ t(t) = 1/8×e^-t/8   [ t > 0]

Now the probability we need

p[T<5] = ₀∫⁵ t(t) dt

=₀∫⁵ 1/8×e^-t/8 dt

= 1/8 ₀∫⁵ e^-t/8 dt

= 1/8 [ (e^-t/8) / -1/8 ]₀⁵

= - [ e^-t/8]₀⁵

= - [ e^-5/8 - 1 ]

= 1 - e^-5/8 = <u>0.4647</u>

Therefore the probability that the time interval between two successive barges is less than 5 minutes is <u>0.4647</u>

<u></u>

b)

Now we find t such that;

p[T>t] = 0.95

so

t_∫¹⁰ t(x) dx = 0.95

t_∫¹⁰ 1/8×e^-x/8 = 0.95

1/8 t_∫¹⁰ e^-x/8 dx = 0.95

1/8 [( e^-x/8 ) / - 1/8 ]¹⁰_t  = 0.95

- [ e^-x/8]¹⁰_t = 0.96

- [ 0 - e^-t/8 ] = 0.95

e^-t/8 = 0.95

take log of both sides

log (e^-t/8) = log (0.95)

-t/8 = In(0.95)

-t/8 = -0.0513

t = 8 × 0.0513

t = 0.4104 (min)

so we convert to seconds

t = 0.4104 × 60

t = <u>24.6 secs</u>

Therefore the time interval t such that we can be 95% sure that the time interval between two successive barges will be greater than t is <u>24.6 secs</u>

6 0
3 years ago
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