Question

Please help and explain how to do this

Answer 1

Answer:

  4√3

Step-by-step explanation:

The distance formula applies. It tells you ...

  distance = √((x2 -x1)² +(y2 -y1)²)

Filling in the given values, you have ...

  distance = √((-√32 -(-4√2))² +(2√3 -(-√12))²)

  = √((-4√2+4√2)² +(2√3 +2√3)²)

  = √(0 + (4√3)²)

  distance = 4√3

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We make use of the fact that ...

  $a\sqrt{b}=\sqrt{a^2b}\\\\\sqrt{32}=\sqrt{16\cdot 2}=4\sqrt{2}\\\\2\sqrt{3}=\sqrt{2^2\cdot 3}=\sqrt{12}$