All categories

3 years ago

Direct variation equation if f(x) varies directly with x and f(x)=-18 when x=3

Mathematics

1 answer:

JulsSmile [24]3 years ago

5 0

F(x)=-6x
Work:
-18÷3=-6

You might be interested in

The sum of three consecutive even numbers 86. Select all the equations below that represent this situation.

Elena-2011 [213]

Answer:
A = X+X+2+X+4=3X+6 =(X+1)+(X+2)+(X+3)
B = 3X+6 =(X+1)+(X+2)+(X+3)
C = not (3X+3)
D = not (3X+3)

3 0

2 years ago

Distributive Property Using GCF<br><br> 25 + 30

postnew [5]

Hey there! I'm happy to help!

Let's look at the factors of each of these numbers.

1,25

5,5

1,30

2,15

3,10

5,6

The greatest common factor between these is 5. Therefore, we divide 25+30 by 5 and put the 5 on the outside.

5(5+6).

This has the same value but it is just written differently.

Have a wonderful day! :D

3 0

3 years ago

Point E is located at (-5,2). Point M is the reflection of point E across the y-axis. What is the distance between E and M?

MArishka [77]

Answer:

The distance is Ten

4 0

2 years ago

Which inequality is represented by the graph?

Svetlanka [38]

C I think not sure I think tho.

7 0

3 years ago

The 1992 world speed record for a bicycle (human-powered vehicle) was set by Chris Huber. His time through the measured 200 m st

Reil [10]

Answer:

a) 30.726m/s and b) 5.5549s

Step-by-step explanation:

a.) What was Chris Huber’s speed in meters per second(m/s)?

Given the distance and time, the formula to obtain the speed is

$v=\frac{d}{t}$ .

Applying this to our problem we have that

$v=\frac{200m}{6.509s}= 30.726m/s$ .

So, Chris Huber’s speed in meters per second(m/s) was 30.726m/s.

b) What was Whittingham’s time through the 200 m?

In a) we stated that $v=\frac{d}{t}$ . This formula implies that

$t=\frac{d}{v}$ .

First, observer that $19\frac{km}{h} =19,000\frac{m}{h}=\frac{19,000}{3,600}m/s= 5.2777m/s$ .

Then, Sam Whittingham speed was equal to Chris Huber’s speed plus 5.2777 m/s. So, $v=30.726\frac{m}{s} +5.2777\frac{m}{s}= 36.003 m/s.$

Then, applying 1) we have that

$t=\frac{200m}{36.003m/s}=5.5549s.$

So, Sam Whittingham’s time through the 200 m was 5.5549s.

5 0

3 years ago