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arsen [322]
3 years ago
10

2 a square root of 2 b square root 3 parentheses for a square root 2 + 380 square root 2 - 80 parentheses equal

Mathematics
1 answer:
velikii [3]3 years ago
5 0

2√2

= 2√2

B)

√3(√2+380√2-80)

= -80√3+381√6


I hope that's help and sorry for the late answer !

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The area of a rectangle is 35 ft2 , and the length of the rectangle is 8 ft less than three times the width. find the dimensions
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The width is five feet and the length is seven feet.
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Which shows one way to determine the factors of x - 9x2 + 5x – 45 by grouping?
EleoNora [17]

Answer:

The last one.

Step-by-step explanation:

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For what value of c is the function defined below continuous on (-\infty,\infty)?
kozerog [31]
f(x)= \left \{ {{x^2-c^2,x \ \textless \  4} \atop {cx+20},x \geq 4} \right


It's clear that for x not equal to 4 this function is continuous. So the only question is what happens at 4.
<span>A function, f, is continuous at x = 4 if 
</span><span>\lim_{x \rightarrow 4} \  f(x) = f(4)

</span><span>In notation we write respectively
</span>\lim_{x \rightarrow 4-} f(x) \ \ \ \text{ and } \ \ \ \lim_{x \rightarrow 4+} f(x)

Now the second of these is easy, because for x > 4, f(x) = cx + 20. Hence limit as x --> 4+ (i.e., from above, from the right) of f(x) is just <span>4c + 20.
</span>
On the other hand, for x < 4, f(x) = x^2 - c^2. Hence 
\lim_{x \rightarrow 4-} f(x) = \lim_{x \rightarrow 4-} (x^2 - c^2) = 16 - c^2

Thus these two limits, the one from above and below are equal if and only if
 4c + 20 = 16 - c²<span> 
 Or in other words, the limit as x --> 4 of f(x) exists if and only if
 4c + 20 = 16 - c</span>²

c^2+4c+4=0&#10;\\(c+2)^2=0&#10;\\c=-2

That is to say, if c = -2, f(x) is continuous at x = 4. 

Because f is continuous for all over values of x, it now follows that f is continuous for all real nubmers (-\infty, +\infty)

4 0
3 years ago
In ΔMNO, m∠M = 57° and m∠N = 75°. Which list has the sides of ΔMNO in order from shortest to longest?
gulaghasi [49]

Answer:

B. MN, NO, OM

Step-by-step explanation:

Recall: In any triangle, the sides and the angles are related in the following way:

*The largest angle and the longest side are opposite each other

*The medium angle and the mid-sized side are opposite each other

*The smallest angle and the shortest side are opposite each other

In ∆MNO, we are given that

m<M = 57° which is opposite to side NO

m<N = 75° which is opposite to side OM

m<O = 180° - (75° + 57°) (sum of triangle)

m<O = 48° which is opposite to side MN

Therefore, we can write the order of shortest to longest side in relation to their opposite angles as follows:

MN, NO, OM

7 0
2 years ago
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