X = -3.
The distance from p(-9, 0, 0) is
d = sqrt((x+9)^2 + y^2 + z^2)
The distance from q(3,0,0) is
d = sqrt((x-3)^2 + y^2 + z^2)
Let's set them equal to each other.
sqrt((x+9)^2 + y^2 + z^2) = sqrt((x-3)^2 + y^2 + z^2)
Square both sides, then simplify
(x+9)^2 + y^2 + z^2 = (x-3)^2 + y^2 + z^2
x^2 + 18x + 81 + y^2 + z^2 = x^2 - 6x + 9 + y^2 + z^2
18x + 81 = - 6x + 9
24x + 81 = 9
24x = -72
x = -3
So the desired equation is x = -3 which defines a plane.

7 0

3 years ago

The complex solution to a quadratic equation is x equals start fraction three plus or minus square root of negative 36 end squar

Naya [18.7K]

The square root of a -36 simplifies to "6i". So you have 3+/- [6i/6]. The 6's cancel each other out leaving 3+/-i. So the "a" is 3 and the "b" is 1

4 0

2 years ago

a minor league baseball team plays 114 games in a season. if the team won 14 more than three times as many games as they lost, h

Rainbow [258]

They will have played with 19 loses 76 wins !

7 0

3 years ago