Answer:
about 2949 feet
Step-by-step explanation:
The geometry of the situation can be modeled by a right triangle. The height of the cliff can be taken to be the side opposite the given angle, and the distance to the coyote will be the side adjacent to the given angle. The relation between these values is the trig function ...
Tan = Opposite/Adjacent
__
<h3>setup</h3>
Filling in the known values, we have ...
tan(6°) = (310 ft)/(distance to coyote)
<h3>solution</h3>
Multiplying by (distance to coyote)/tan(6°) gives ...
distance to coyote = (310 ft)/tan(6°) ≈ 310/0.105104 ft
distance to coyote ≈ 2949.453 ft
The coyote is about 2949 feet from the base of the cliff.
No its smaller............................
Answer:
81.12 cm²
Step-by-step explanation:
The area for a semicircle can be figured with this formula: (πr²)/2. The triangle's area formula is bh/2.
(3.14 * 4²)/2 + (14 * 8)/2 <em>(Work the operations in parentheses first.)</em>
(3.14 * 16)/2 + 112/2
50.24/2 + 112/2 (<em>Divide 50.24 by 2. Do the same for 112.)</em>
25.12 + 56 (<em>Add 25.12 & 56.)</em>
81.12 cm²
The area of the figure is 81.12 cm².
Answer:
-21
28
Step-by-step explanation:
1) if r = -4
Substitute r = -4 in 3r - 9
= 3 * (-4) - 9
= -12 - 9
= -21
2) ( 4 / 7 ) * x = 16
4 * x = 16 * 7
x = 4 * 7
x = 28
Answer:
2.8
Step-by-step explanation:
this is my best guess