Answer:
See below
Step-by-step explanation:
Vertical velocity will be affected by gravity in this scenario
df = do + vo t + 1/2 a t^2 do = original height = 4 ft a = -32.2 ft/s^2
<u>df = 4 + 89 t - 1/2 (32.2) t^2 df = height</u>
<u />
On the way up and the way down, the ball may reach height of 102.2125 ft :
102.2125 = 4 + 89 t - 1/2 (32.2) t2 re-arrange to:
-16.1 t^2 + 89t - 98.2125 =0
Use Quadratic Formula to find <u>t = 1.5 and 4.0 s </u>
Just subtract the following number from the preceding one.
48- 3= 45
3- 45= -42.
Since all you’re saying is evaluate ∫12–2
I’m assuming the answer would be 1/(1+x)(1-x)
Answer:
x^2-4x+4-(x^2+6x+9)
Step-by-step explanation:
=x^2-4x+4-x^2-6x-9
=-10x - 5
I hope this help you I gess 16
