Answer:
a) The function is constantly increasing and is never decreasing
b) There is no local maximum or local minimum.
Step-by-step explanation:
To find the intervals of increasing and decreasing, we can start by finding the answers to part b, which is to find the local maximums and minimums. We do this by taking the derivatives of the equation.
f(x) = ln(x^4 + 27)
f'(x) = 1/(x^2 + 27)
Now we take the derivative and solve for zero to find the local max and mins.
f'(x) = 1/(x^2 + 27)
0 = 1/(x^2 + 27)
Since this function can never be equal to one, we know that there are no local maximums or minimums. This also lets us know that this function will constantly be increasing.
The area of a circle is <span>πr²
the outer circle area = </span><span>π 4x²
the inside circle area = </span>π.6²=36<span>π
</span>the outer circle area - <span>the inside circle area = </span><span>he shaded region
</span>π 4x² - 36π =<span>220π cm2 it implies x²-9 =55 and x²=64, and x =sqrt(64)=8
the value of x is 8</span>
