Answer:
we need to see the whole graph to determine the domain and range please
Step-by-step explanation:
Answer:
The correct option is A.
Step-by-step explanation:
Domain:
The expression in the denominator is x^2-2x-3
x² - 2x-3 ≠0
-3 = +1 -4
(x²-2x+1)-4 ≠0
(x²-2x+1)=(x-1)²
(x-1)² - (2)² ≠0
∴a²-b² =(a-b)(a+b)
(x-1-2)(x-1+2) ≠0
(x-3)(x+1) ≠0
x≠3 for all x≠ -1
So there is a hole at x=3 and an asymptote at x= -1, so Option B is wrong
Asymptote:
x-3/x^2-2x-3
We know that denominator is equal to (x-3)(x+1)
x-3/(x-3)(x+1)
x-3 will be cancelled out by x-3
1/x+1
We have asymptote at x=-1 and hole at x=3, therefore the correct option is A....
3(2(5)+4)-5
3(10+4)-5
30+12-5
42-5
37
Answer: The answer is (B). 1.01257486...
Step-by-step explanation: We are given four real numbers out of which we are to select the one which is irrational.
Option (A) is 0.12, in which the digits after the decimal are terminating. So, the number is rational.
Option (B) is 1.01257486..., the digits after the decimal are non-terminating and non-recurring. So, the number is irrational.
Option (C) is 0.1212121212..., in which the digits after the decimal are non-terminating and recurring. So, the number is rational.
Option (D) is 0.11111111..., in which the digits after the decimal are non-terminating and repeating. So, the number is rational.
Thus, (B) is the correct option.
