The area of a rectangle is (length) times (width).
So you have to find a pair of numbers that multiply to produce 6 .
If you only stick to whole numbers, then I don't think there are three
different ones. You're going to need one pair that multiply to 6 and
are not both whole numbers.
After I explain how to solve problems, I hate to give answers. But with
all due respect, I have a feeling that I haven't nudged you enough yet
for you to use my explanation to find the answers on your own.
So here are some answers:
1 and 6
2 and 3
and sets of dimensions that are not both whole numbers, like
0.6 and 10
1.2 and 5
1.25 and 4.8
1.5 and 4
2.4 and 2.5
Please, share just ONE problem at a time. Thanks.
<span>Solve 2x^2-12x+20=0:
Simplify this by dividing each term by 2: x^2 - 6x + 10 = 0
Identify a, b and c: a=1, b=-6 and c=10. Then b^2=36.
Write out the solutions using the quadratic formula:
6 plus or minus sqrt(36-40)
x = ---------------------------------------
2
sqrt(36-40) = sqrt(-4) = plus or minus i2
Then:
6 plus or minus i2
x = --------------------------- (answer)
2</span>
Answer:
The m∠ U is 72°.
Step-by-step explanation:
Given:
To find :
Solution:
The sum of the measures of the interior angles of a polygon with 'n' sides is given as
Here we have n = 5 on substituting the values we get
Therefore,
m∠ U is 72°.
