All categories

3 years ago

What is the surface area of the triangular prism? A. 13 in.2 B. 36 in.2 C. 78 in.2 D. 84 in.2

Mathematics

1 answer:

NISA [10]3 years ago

4 0

Answer :36in2

example:
my math teacher told me

You might be interested in

Need help with Trigonometry

Masteriza [31]

Answer:

Step-by-step explanation:

using Pythagorean theory.

equate it to the hypotenus.

thus- hyp sq=adjacent sq +opposite sq

7 0

2 years ago

I suck at math I need help

GaryK [48]

Answer:

b=74

Step-by-step explanation:

You just gotta use sum of angles in a triangle and sum of angles on a straight line.

3 0

3 years ago

Read 2 more answers

For which equation is x = 1 a solution?

andreev551 [17]

Answer:

C x+3=1 is the answer to your question

3 0

3 years ago

What’s up solution should be used to rewrite 16(x^3+1)^2-22(x^3+1)-3=0

ladessa [460]

Answer:

x = cuberoot( -9/8)= -1.04004 or x = cuberoot(1/2)=0.7937

Step-by-step explanation:

let y = x^3 + 1

we have:

16*(y) ^2 - 22 (y) - 3 = 0

16 = 2* 8

-3 = -3* 1

8*-3 + 2 = -24 + 2 = -22

Factor as (8y + 1)(2y - 3) = 16 (y)^2 - 22(y) - 3 = 0

so (8y + 1) = 0 or 2y - 3 = 0

y = -1/8 OR y = 3/2

with y = x^3 + 1

solve for x

-1/8 = x^3 + 1

x^3 = - 9/8

x = cuberoot( -9/8)

about x = -1.04004

or 3/2 = x^3 + 1

1/2 = x^3

x = cuberoot( 1/2 ) = 0.7937

3 0

3 years ago

Find the vertex of y = x2 + 14x − 40 by completing the square. A. (−7, 89) B. (−89, −7) C. (7, 89) D. (−7, −89)

irga5000 [103]

Alright, lets get started.

$y = x^2 + 14 x - 40$

For making complete square, we will add and subtract 49 in this

$y = x^2 + 14 x - 40 + 49 - 49$

$y = x^2 + 14 x + 49 -40 - 49$

$y = (x+7)^2 - 40 - 49$

$y = (x+7)^2 - 89$

Comparing the standard equation of parabola

$y = a (x-h)^2 + k$ where (h,k) are vertex

So, comparing the equation with standard one, h, k would be = (-7 , -89)

So, the vertex are (-7 , -89) : Answer

Hope it will help :)

8 0

3 years ago