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muminat
3 years ago
7

Explain how to implement two stacks in one array A[1..n] in such a way that neither stack overflows unless the total number elem

ents in both stacks together exceeds n. Show your work for the new PUSH,POP operations
Computers and Technology
1 answer:
algol [13]3 years ago
5 0

Answer:

Check explanation

Explanation:

Two stacks can make use of one array by utilizing various stack pointers that begins from different ends of an array. Looking at the array A[1...n], the first stack will drive elements that starts from position 1 as well as to move its' pointer to n.

The Second stack will begin at the n position and motion its' pointer to 1. The best likely divide is to offer each stack a half of an array. whenever any of two stacks transverse the half-point, an overflow can happen but for that overall number of elements, it must be n

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<u> A. It uses binary numbers in its algorithm</u>

Explanation:

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2 years ago
Read 2 more answers
Write a program that allows a user to choose to roll between 1 and 100 dice between 1 and 1000 times
s344n2d4d5 [400]

Answer:

Here is a Python program that allows a user to choose to roll between 1 and 100 dice between 1 and 1000 times. The program uses a while loop to continuously prompt the user for input until they enter a valid number of dice and rolls. It also uses a for loop to simulate the dice rolls and a random module to generate random numbers for the dice rolls.

import random

while True:

   # Prompt the user for the number of dice to roll

   num_dice = int(input("Enter the number of dice to roll (1-100): "))

   if num_dice < 1 or num_dice > 100:

       continue

   # Prompt the user for the number of rolls to perform

   num_rolls = int(input("Enter the number of rolls to perform (1-1000): "))

   if num_rolls < 1 or num_rolls > 1000:

       continue

   # Simulate the dice rolls and print the results

   for i in range(num_rolls):

       roll = 0

       for j in range(num_dice):

           roll += random.randint(1, 6)

       print(f"Roll {i+1}: {roll}")

   # Ask the user if they want to roll again

   again = input("Roll again? (Y/N): ").upper()

   if again != "Y":

       break

Explanation:

In this program, we first import the random module to use its randint function to generate random numbers for the dice rolls. We then enter a while loop that will continuously prompt the user for input until they enter a valid number of dice and rolls. Within the while loop, we prompt the user for the number of dice to roll and the number of rolls to perform. If the user enters an invalid number of dice or rolls, we continue back to the beginning of the loop and prompt the user again.

Once the user has entered a valid number of dice and rolls, we use a for loop to simulate the dice rolls. For each roll, we use another for loop to roll the specified number of dice and add up the results. We then print the total for each roll. After all of the rolls have been performed, we ask the user if they want to roll again. If they enter "Y", we continue back to the beginning of the while loop to prompt them for new input. If they enter anything else, we break out of the while loop and end the program.

Overall, this program allows a user to choose to roll between 1 and 100 dice between 1 and 1000 times, and simulates the dice rolls using random numbers and loops.

8 0
10 months ago
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