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poizon [28]
3 years ago
15

Which page in a web site do viewers usually see first?

Computers and Technology
1 answer:
kompoz [17]3 years ago
5 0
The home page, i think
You might be interested in
What are two fundamental components of data structures?
Fed [463]
Organization and access method.

Hope this helped! :)

- Jujufire
8 0
3 years ago
An enhancement to a computer accelerates some mode of execution by a factor of 10. The enhanced mode is used 50% of the time, me
Ann [662]

Answer:

The answer is "5.5 and 90.90%"

Explanation:

For point 1:

To calculate the speed from fast mode, its run time without enhancement should be worked out. Designers are aware of which two selves are implicated throughout the accelerated project planning: the empty (50 \%) and the increased stages (50 \%).

Although not enhanced, this would take almost as long (50 \%) and for the combine to give phase; even so, the increased phase would've been 10 times longer, as well as 500 \%. Thus the corresponding total speed without enhancement is =50\% + 500\% = 550\%.

Its overall speed is:

=\frac{\text{Accelerated runtime}}{ \text{accelerated  runtime}} = \frac{550 \%}{ 100 \%}= 5.5

For point 2:

We re-connect these figures in Amdahl's Law throughout order to identify how long it would take for both the initial implementation:

\text{Vectorized fraction}= \frac{\text{Overall velocity}\times \text{Accelerated acceleration}-\text{Accelerated acceleration}}{\text{Overall acceleration} \times \text{Accelerated acceleration}-\text{Overall acceleration}}

                              = \frac{5.5  \times 10 -10 }{ 5.5 \times 10 - 5.5}\\\\=\frac{45}{49.5}\\\\=0.9090\\\\=90.90\%

5 0
2 years ago
A detective agency is looking to bust an arms sale. According to available intelligence, the sale is likely to happen in one of
Paha777 [63]

Answer:

Probability Distribution={(A, 4/7), (B, 2/7), (C, 1/7)}

H(X)=5.4224 bits per symb

H(X|Y="not C")=0.54902 bits per symb

Explanation:

P(B)=2P(C)

P(A)=2P(B)

But

P(A)+P(B)+P(C)=1

4P(C)+2P(C)+P(C)=1

P(C)=1/7

Then

P(A)=4/7

P(B)=2/7

Probability Distribution={(A, 4/7), (B, 2/7), (C, 1/7)}

iii

If X={A,B,C}

and P(Xi)={4/7,2/7,1/7}

where  Id =logarithm to base  2

Entropy, H(X)=-{P(A) Id P(A) +P(B) Id P(B) + P(C) Id P(C)}

=-{(1/7)Id1/7 +(2/7)Id(2/7) +(4/7)Id(4/7)}

=5.4224 bits  per symb

if P(C)  =0

P(A)=2P(B)

P(B)=1/3

P(A)=2/3

H(X|Y="not C")= -(1/3)Id(I/3) -(2/3)Id(2/3)

=0.54902 bits per symb

4 0
3 years ago
Given a vector of students, the function FinalAvg is supposed to return the average final exam score across all the students in
alexandr1967 [171]

Answer:

The C++ code is given below with appropriate comments

Explanation:

#define CATCH_CONFIG_MAIN //This tells Catch to provide a main()

#include"catch.hpp" //Header for Catch Framework

double FinalAvg( vector <int> students) // Function to calculate average.

{

double sum =0;

int i;

for( i=0;i<v.size();i++) sum+= v[i];

return v.empty() ? 0.0 : (double(sum)/ v.size());

}

vector<int> func(int argvq[ ]) // This function is made because we can not provide vector in command line argument that's why we used array which is then conerted into vector.

{

vector<int> v;

int j;

int l= sizeof(argvq)/sizeof(argvq[0]);

for(j=0;j<l;j++)

v.push_back(argq[j]);

return v;

}

TEST_CASE(" Final Average marks are computed","[func]") // TEST_ CASE macro to take one or more arguments

{

REQUIRE( func(9,5,-7) == 7); // We write our individual test assertions using the REQUIRE macro.

REQUIRE(func(2,4,6,-2) ==4);

}

Explanation Using different IDE:

#include<bits/stdc++.h>

using namespace std;

double FinalAvg(vector<int> students)

{

double sum=0;

for(int i=0;i<v.size();i++) sum+= v[i];

return v.empty() ? 0.0 : (double(sum)/v.size());

}

int main()

{

vector<int> v;

int i;

while(cin>>i&&i>0) v.push_back(i);

cout<<Final Avg(v);

return 0;

}

8 0
3 years ago
Is(are) input value(s) to use with a program to test the accuracy of the output.
Law Incorporation [45]

Answer:

test cases

Explanation:

5 0
3 years ago
Read 2 more answers
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