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Fittoniya [83]
3 years ago
7

Tom ate 1/6of the left overs.How much pie did he eat.

Mathematics
2 answers:
castortr0y [4]3 years ago
3 0

Answer:

1/6

Step-by-step explanation:

He ate 1/6 of the pie , because thats how much he ate

XD

lakkis [162]3 years ago
3 0

Answer:

Step-by-step explanation:

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What is the range of this set of data?<br> 111.97, 63, 84, 100, 119,72
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Answer:

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Step-by-step explanation:

The range of a data set is the difference between the largest and the smallest values in that data set. In this case, the largest value in the data set is 119, and the smallest is 63. 119-63=56, which is the range. Hope this helps!

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Mr. Jenkins is going to buy museum tickets for a class trip. The museum director gives him the following prices:
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If A = (0, 0) and B = (6, 3), what is the length of ? A.7.73 units B.6.24 units C.5.20 units D.6.71 units
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If outliers are discarded, then the retirement savings by residents of Econistan is normally distributed with a mean of $100,000
zavuch27 [327]

Answer:

P(X>117000)=P(\frac{X-\mu}{\sigma}>\frac{117000-\mu}{\sigma})=P(Z>\frac{117000-100000}{20000})=P(z>0.85)

And we can find this probability using the complement rule and the normal standard table or excel:

P(z>0.85)=1-P(z

The firgure attached illustrate the problem

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the retirement savings of a population, and for this case we know the distribution for X is given by:

X \sim N(100000,20000)  

Where \mu=100000 and \sigma=20000

We are interested on this probability

P(X>117000)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>117000)=P(\frac{X-\mu}{\sigma}>\frac{117000-\mu}{\sigma})=P(Z>\frac{117000-100000}{20000})=P(z>0.85)

And we can find this probability using the complement rule and the normal standard table or excel:

P(z>0.85)=1-P(z

The firgure attached illustrate the problem

7 0
2 years ago
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