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masha68 [24]
3 years ago
13

At 6:00 AM, the outside temperature was –14⁰. By noon. the outside temperature had risen by 8⁰. What was the outside temperature

at noon?
a. –22⁰
b. –6⁰
c. 6⁰
d. 22⁰
Mathematics
2 answers:
MrRissso [65]3 years ago
8 0
The answer is b. -6°
-14+8= -6
svlad2 [7]3 years ago
3 0
-14⁰+8⁰=[-6⁰].
It's Ok B.-6
⁰
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Step-by-step explanation:

Hi, to answer this question we have to apply the compounded interest formula:

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r =interest rate (decimal form)

t = time (in this case years)

Replacing with the values given:

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A = 2,277.5

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8 0
3 years ago
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Furkat [3]

Answer:

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Step-by-step explanation:

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rosijanka [135]

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Step-by-step explanation:

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