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torisob [31]
4 years ago
15

At an international conference, flags from 8 different countries will be displayed. Of these flags, 4 are from the continent of

Africa and 4 flags are from the continent of Europe. The flags will be displayed in a row, alternating between continents. A flag from Africa will be in the first position. In how many ways can the flags be displayed?
Mathematics
1 answer:
lorasvet [3.4K]4 years ago
3 0

Answer:

96 ways

Step-by-step explanation:

Let´s call flags of countries from Africa as  A₁,  A₂, A₃, A₄, and from Europe as  E₁, E₂, E₃ and E₄

We have to display the flags always beginning with one flag from Africa let´s take A₁

For that flag, we have 4! possibilities Then 4! is:

4*3*2*1  = 24

As we have 4 different Flags from Africa, we will have

4*24 = 96  possibilities

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Suppose a batch of metal shafts produced in a manufacturing company have a standard deviation of 1.4 and a mean diameter of 212
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Answer:

P(211.9  

And using the normal standard table or excel we can find this probability with this difference:

P(-0.639

Step-by-step explanation:

For this case we define the random variable X="metal shafts" produced in a manufacturing company, and we have the following properties given:

E(X)= 212, \sigma = 1.4

Previous concepts

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

They select a sample if size n=4, by the central limit theorem the distribution for the sample mean is given by:

\bar X \sim N(\mu=212, \frac{1.4}{\sqrt{80}}= 0.1565)

We are interested on this probability  

P(211.9  

And the best way to solve this problem is using the normal standard distribution and the z score given by:  

z=\frac{\bar x-\mu}{\frac{\sigma}{\sqrt{n}}}  

If we use this formula we got this:

P(211.9  

And using the normal standard table or excel we can find this probability with this difference:

P(-0.639

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Pls I need answer quick, pls
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Answer:

its a hope this helps

Step-by-step explanation:

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