Answer: The required solution is 
Step-by-step explanation:
We are given to solve the following differential equation :

where k is a constant and the equation satisfies the conditions y(0) = 50, y(5) = 100.
From equation (i), we have

Integrating both sides, we get
![\int\dfrac{dy}{y}=\int kdt\\\\\Rightarrow \log y=kt+c~~~~~~[\textup{c is a constant of integration}]\\\\\Rightarrow y=e^{kt+c}\\\\\Rightarrow y=ae^{kt}~~~~[\textup{where }a=e^c\textup{ is another constant}]](https://tex.z-dn.net/?f=%5Cint%5Cdfrac%7Bdy%7D%7By%7D%3D%5Cint%20kdt%5C%5C%5C%5C%5CRightarrow%20%5Clog%20y%3Dkt%2Bc~~~~~~%5B%5Ctextup%7Bc%20is%20a%20constant%20of%20integration%7D%5D%5C%5C%5C%5C%5CRightarrow%20y%3De%5E%7Bkt%2Bc%7D%5C%5C%5C%5C%5CRightarrow%20y%3Dae%5E%7Bkt%7D~~~~%5B%5Ctextup%7Bwhere%20%7Da%3De%5Ec%5Ctextup%7B%20is%20another%20constant%7D%5D)
Also, the conditions are

and

Thus, the required solution is 
Answer:
they can be lined up from front,side, back
Step-by-step explanation:
if u line them by side their in a straight line and hips faced to camera,or smallest to tallest in face front camera or back point of view in jumping, or holding hands.
we have

Complete the square. Remember to balance the equation by adding the same constants to each side


Rewrite as perfect squares


therefore
the answer is
the solutions are

1) Data:
Meal calories consumed
Breakfast 400 cal
Lunch 350 cal
Dinner x
------------------
Total 400 + 350 + x = 750 + x
2) Equation: <span>
She consumes 2/3 of her daily calories at dinner => (2/3)[750+x] = x
3) Analyze each statement:
</span><span>a) Lena
consumed 1500 cal at dinner.
Solve the equation to find if the statement is true:
</span>
<span><span>(2/3)[750+x] = x</span>
2(750+x) = 3x
1500 + 2x = 3x
1500 = 3x - 2x
x = 1500
Conclusión: TRUE stament.
b) Do you equation 2/3 (x+400+350)=x can be
used to model the situation.
That is the same equation that I found above.
Conclusion: TRUE statement
c) Lena consumed 500 cal at dinner.
She consumed (2/3) * 1500 = 500 cal
Conclusion: TRUE statement
d) Lena
consumed 1000 cal at dinner.
No, we calculated that she consumed 500 cal at dinner.
Conclusion: FALSE statement
e) The equation 2/3(x)=x(400+350) can be used
to model the situation.
No: (2/3) x = 500 and x(400+350) = 500*750 = 375,00, which are not equal.
Conclusion: FALSE statement.
f) The equation 2/3x(400+350)=x Can’t be used to
model the situation
No: in that equation the variable x cancels out because it appears a factor at both sides.
</span>Conclusion: TRUE statement