The answer is
<span>A. 12x2 + 6x
solution
</span><span>y = 4x3 + 3x2 + 2
</span><span>y'(x) = 12x^2 + 6x
</span>
Hi there!
The question is asking us to simplify the expression (x² + 3x - 7)(2x - 5) and write the answer in standard form. Here is how you do that -
Original: (x² + 3x - 7)(2x - 5)
Break it apart - [(x² + 3x - 7)(2x)] + [(x² + 3x - 7)(-5)]
Simplify -
2x³ + 6x² - 14x - 5x² - 15x + 35
Now, combine like terms -
2x³ + x² - 29x + 35
Therefore, the answer to your query is 2x³ + x² - 29x + 35. Hope this helps!
Answer:
The answer is D) No; Y doesn't vary directly with x.
Step-by-step explanation:
It isn't A because:
y=2x:
2(2)=4=y Not true, 2(4)=8=y Not true, 2(6)=12=y Not true
It isn't B:
y=5x
5(2)= 10=y True, 5(4)=20=y Not true, 5(6)=30=y Not true
It isn't C:
y=7x
7(2)=14=y Not true, 7(4)=28=y Not true, 7(6)=42=y Not true
Y = x^2 + 2x - 1 = x^2 + 2x + 1 - 1 - 1 = (x + 1)^2 - 2
The vertex of a parabola given by y = a(x - h)^2 + k is (h, k).
Therefore, the vertex of y = (x + 1)^2 - 2 is (-1, -2)
