Step-by-step explanation:
The solution to this problem is very much similar to your previous ones, already answered by Sqdancefan.
Given:
mean, mu = 3550 lbs (hope I read the first five correctly, and it's not a six)
standard deviation, sigma = 870 lbs
weights are normally distributed, and assume large samples.
Probability to be estimated between W1=2800 and W2=4500 lbs.
Solution:
We calculate Z-scores for each of the limits in order to estimate probabilities from tables.
For W1 (lower limit),
Z1=(W1-mu)/sigma = (2800 - 3550)/870 = -.862069
From tables, P(Z<Z1) = 0.194325
For W2 (upper limit):
Z2=(W2-mu)/sigma = (4500-3550)/879 = 1.091954
From tables, P(Z<Z2) = 0.862573
Therefore probability that weight is between W1 and W2 is
P( W1 < W < W2 )
= P(Z1 < Z < Z2)
= P(Z<Z2) - P(Z<Z1)
= 0.862573 - 0.194325
= 0.668248
= 0.67 (to the hundredth)
Based on the right angle triangle and the given parameters, cos K = 5/13
<h3>Trigonometric ratios</h3>
- sin = opposite / hypotenuse
- cos = adjacent / hypotenuse
- Tan = opposite / adjacent
Given parameters:
- Hypotenuse = 13
- Adjacent = 5
- Opposite = 12
Therefore,
cos K = adjacent / hypotenuse
cos K = 5/13
Learn more about right triangle:
brainly.com/question/2217700
#SPJ1
Answer:
in steps
Step-by-step explanation:
12 - 6 x 2 + 3 = 3
(12 - 6 ÷ 2) x 3 = 27 .... ??
12 ÷ 6 + 2 x 3 = 8
12 ÷ 6 + 2 + 3 = 7
12 + 6 ÷ 2 + 3 = 18
Answer:
The formula for area of a parallelogram is either 
or 
.
Step-by-step explanation:
If base and vertical height of a parallelogram are given, then the area of the parallelogram is:
Where, <em>b</em> is base and <em>h</em> is the vertical height of the parallelogram.
If measures of both diagonals are given, then the area of the parallelogram is:
Where, 
are the two diagonals of the parallelogram.
