Ask question

Ask question

All categories

3 years ago

9

Can you determine the zeros of F(x)=x^2 +64 by using a graph?

2 answers:

gladu [14]3 years ago

7 0

No you can't because there wasn't any zeros in this function.

yKpoI14uk [10]3 years ago

4 0

The solution to the problem is as follows:

y = x^2 + 64

f(x) = 0 = x^2 + 64

x^2 = -64

x = √-64

so..

x = 8i ; x = -8i

<span>Don't forget the negative root.
</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

You might be interested in

Can you help my brother so I can help him! How can you subtract 5 2/12 - 1 9/12

Lana71 [14]

Answer: $\frac{41}{12}$ , or as a mixed number, 3 $\frac{5}{12}$

Step-by-step explanation:

It helps to simplify them.

6 0

3 years ago

Find the vertex of the function given below.<br> y = 3x2 + 6x +1

anastassius [24]

Answer: The coordinates of the vertex are : (-1,-2)

Step-by-step explanation: To find the x coordinate, we use the formula:

Xv = -b/2a = -6/(2.3) = -6/6 = -1

Replacing x by -1, we write:

y = 3. (-1)^2 + 6. (-1) +1 = 3 - 6 + 1 = -2

8 0

3 years ago

Explain how you could use 6×9 = 54 to find 54÷9?

erastova [34]

Look at the original equation. 6x9=54. all you are doing is switching numbers up. 54/9=6. or 54/9=6.

5 0

3 years ago

Read 2 more answers

PLZ HELP ASAP!! MARKING BRAINIEST!! Plot the axis of symmetry and the vertex for this function: h(x) = (x − 5)2 − 7.

jeka94

Answer:

see below

Step-by-step explanation:

h(x) = (x − 5)^2 − 7

This is in vertex form

y = a( x-h)^2 + k

where ( h,k) is the vertex and x=h is the axis of symmetry

( 5,-7) is the vertex and x=5 is the axis of symmetry

8 0

3 years ago

Evaluate 8x – y if x = 3 and y = 6. 18 5 11 45

uranmaximum [27]

To find the answer, we substitute in the values of y and x
(8 × 3) - 6 = 24 - 6 = 18

So your answer is 18

I hope this helps!

5 0

3 years ago