Answer:
The area of triangle K is 16 times greater than the area of triangle J
Step-by-step explanation:
we know that
If Triangle K is a scaled version of Triangle J
then
Triangle K and Triangle J are similar
If two triangles are similar, then the ratio of its areas is equal to the scale factor squared
Let
z -----> the scale factor
Ak ------> the area of triangle K
Aj -----> the area of triangle J
so

we have

substitute



therefore
The area of triangle K is 16 times greater than the area of triangle J
152.4cm. 2.54cm = 1in. 60in x (2.54cm/1in) = 152.4cm.
The missing angle would be 35 degrees. The straight line adds up to 180 and the right angle would be 90 degrees. 180-90-55 would be 35.
Answer:
i6 sqrt 5
Step-by-step explanation:
It cannot be 12i sqrt 5 as this is 26.8326....
it cannot be 18i sqrt 5 as this is 40.249...
It cannot be 8i sqrt 5 as this is 17.888....
It cnanot be 8i sq rt 10 as this is 25.298....
i6 sq rt 5 = sqrt -180
Answer:
y = 7x - 1 is the answer to the question