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LuckyWell [14K]
3 years ago
14

The sampling distribution of certain statistical measures shows a normal distribution which of the following is an unbiased esti

mator that has a graph that is normally distributed and is not skewed
a. proportion
b. median
c. range
d. variance
Mathematics
2 answers:
PilotLPTM [1.2K]3 years ago
7 0

GACA

Answer: 1. B) Normal distribution

2. D) Variance, mean, proportion

3. D) normal distribution

4. D) normal distribution

5. A) proportion

6. A) median

7. C) this is just one sample. The sampling distribution of the mean requires repeating this process with the same sample several times

8. A) not a normal distribution

9. B) mean, variance, proportion

10. A) the sampling distribution of the variance requires repeating this process with the same sample several times. So this does not compare to the sampling distribution of the variance

Step-by-step explanation: 100% :)

svlad2 [7]3 years ago
4 0

Answer:

A) Proportion.

Step-by-step explanation:

The distribution of sample proportions leads or may tends to approximate a normal distribution and is an unbiased estimator that has a graph that is usually distributed and is not skewed. In other words, simply, we can also say that the population proportion is basically defined to be as the mean of the sample proportion. The population proportion is basically equaled the expected value of the sample proportion.

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Step-by-step explanation

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3 years ago
What is the correct negation of "There is someone in Spain who speaks at least 10 languages"?1) "Everyone in Spain speaks at lea
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Answer:

4) "Everyone in Spain speaks at most 9 languages."

Step-by-step explanation:

A negation is a statement that contradicts the original statement. Since the original statement regards people in Spain, options 2, 5, 6 and 7 can be ruled out as they refer to speakers outside of Spain.

Evaluating the remaining statements.

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3 years ago
The federal government would like to test the hypothesis that the average age of men filing for Social Security is higher than t
mixas84 [53]

Answer:

The 90% confidence interval is  -0.3433<  \mu_1 - \mu_2 < 2.1433

Step-by-step explanation:

From the question we are told that

   The sample mean for men is  \= x_1 = 64.5 \ years

    The sample mean for women is  \= x_2 = 63.6 \ years

     The sample size for men  is   n_1 = 35

      The sample size for women is  n_2 = 39

      The standard deviation for men is s_1 = 3.0

       The standard deviation for women is  s_2 = 3.5

From the question we are told the confidence level is  90% , hence the level of significance is    

      \alpha = (100 - 90 ) \%

=>   \alpha = 0.10

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.645

Generally the standard error is mathematically represented as

     SE = \sqrt{\frac{s_1^2 }{n_1}  + \frac{s_2^2}{n_2} }

=>  SE = \sqrt{\frac{3^2 }{35}  + \frac{3.5^2}{39} }

=>  SE = 0.7558

Generally the margin of error is mathematically represented as

       E =  Z_{\frac{\alpha }{2} } *  SE

=>     E =  1.645  *  0.7558

=>     E =  1.2433

Generally 90% confidence interval is mathematically represented as  

      (\= x_1 - \= x_2) -E <  \mu_1 - \mu_2 <  (\= x_1 - \= x_2) -E

=>    (64.5 - 63.6) -1.2433<  \mu_1 - \mu_2

=>    -0.3433<  \mu_1 - \mu_2 < 2.1433

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