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2 years ago

7

5 − (x + 5) > −2(x + 4)

2 answers:

Agata [3.3K]2 years ago

8 0

$5-(x+5) > -2(x+4)\\\\5-x-5 > -2\cdot x-2\cdot4\\\\5-5-x > -2x-8\\\\-x > -2x-8\ \ \ |add\ 2x\ to\ both\ sides\\\\x > -8\to x\in(-8;\ \infty)$

Georgia [21]2 years ago

4 0

X><span>−<span>8 answer <<

step by step work

</span></span>Let's solve your inequality step-by-step.<span><span>5−<span>(<span>x+5</span>)</span></span>><span>−<span>2<span>(<span>x+4</span>)</span></span></span></span>
Step 1: Simplify both sides of the inequality.<span><span>−x</span>><span><span>−<span>2x</span></span>−8</span></span>
Step 2: Add 2x to both sides.<span><span><span>−x</span>+<span>2x</span></span>><span><span><span>−<span>2x</span></span>−8</span>+<span>2<span>x</span></span></span></span>

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Solve for a: a(a-3) =100

marissa [1.9K]

$a(a-3) =100\\
a^2-3a-100=0\\
\Delta=(-3)^2-4\cdot1\cdot(-100)=9+400=409\\
\sqrt{\Delta}=\sqr{409}\\
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Step-by-step explanation:

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2 years ago

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What is the equivalent of 3/6

Maslowich

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3 years ago

If f(x) = 2x2 + 1, what is f(x) when x = 3? a.1 b.7 c.13 d.19

prohojiy [21]

<u>Answer:</u>

The value of f(x) = $2x^2 + 1$ when x=3 is 19, hence the correct option is ‘d’.

<u>Solution:</u>

A two degree polynomial equation is given in the question.

The equation is:

$F(x)=2 x^{2}+1$

We need <em>to find the value of f(x) when the value of x is 3. </em>

To solve a question like this we have to substitute the given value of x in the given equation and then simplify it.

Now let's substitute the value of x in the given equation.

$F(x)=2(3)^{2}+1$

First we square the number 3 and then multiply it with 2 and then add 1.

This is done because of the BODMAS rule, in which multiplication is given higher preference as compared to addition.

On solving the equation we get,

F(x)=2×9+1

F(x)=18+1

F(x)=19.

Therefore the value of f(x) when x=3 is 19.

Hence the correct option is ‘d’.

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3 years ago

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