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nydimaria [60]
3 years ago
5

How many solutions are possible for a system of equations containing exactly one linear and one quadratic equation? (Select all

that apply). 0 1 2 3 4
Mathematics
1 answer:
galina1969 [7]3 years ago
6 0
Remember that a quadratic equation is a parabola. The equation is of the type y = Ax^2 + Bx + C


A linear equation is a straight line. The equation is of the type y = MX + N


The soluction of that system is Ax^2 + Bx + C = MX + N

=> Ax^2 + (B-M)x + (C-N) = 0


That is a quadratic equation.


A quadratic equation may have 0, 1 or 2 real solutions. Those are all the possibilitis.


So you must select 0, 1 and 2.


You can also get to that conclusion if you draw a parabola and figure out now many point of it you can intersect with a straight line.


You will realize that depending of the straight line position it can intersect the parabola in none point, or one point or two points.  
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{(1,-3), (-2,3), (5,1), (6,4)}
ira [324]
I don't know what is the question

but this is the pictures of the points




good luck

6 0
3 years ago
What is 14^5 divided by 14^-9 explain answer
yuradex [85]
I believe the answer is 1.1112007e+16 because 14^5=537824 and 14^-9= 4.8400258e-11. You divide both numbers and get 1.1112007e+16
8 0
2 years ago
1. What is the formula for compound interest?
Rus_ich [418]

Answer:

  1.   CI = P (1 + \frac{r}{100} )^ n - P

        CI = A - P

      Where P is Principal

      R is interest rate

      n is number of years

   2. a. Semi annually - four times in a year

       b. Monthly           -  two times in a year

       c.  annually          -  once in a year

Step-by-step explanation:

1.  Money is said to be lent at compound interest , when the interest has become due at certain fixed period say, one year, half year, etc.., is given not paid to money lender, but is added to sum lent . The amount thus obtained become principal for next month and this process repeat until last period .

i.e CI = Final period - Initial period

or CI = A - P

or CI = P(1+ \frac{r}{100}) ^n - P

2. (a) Semi annually

        A = P (1 + \frac{r}{4 * 100} )^ n × 4

   (b)  Monthly

       A = P (1 + \frac{r}{2 * 100} ) ^ n × 2

   

   (c)  Annually

       A = P (1 + \frac{r}{100} ) ^ n

3 0
3 years ago
How do you become an administrator?
antoniya [11.8K]

How do you become an administrator?

I think answering a lot of questions and dont get warnings

8 0
3 years ago
Help pleasee! Thank uu
ololo11 [35]

Answer:

The answer is the 2nd option

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
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