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nydimaria [60]
3 years ago
5

How many solutions are possible for a system of equations containing exactly one linear and one quadratic equation? (Select all

that apply). 0 1 2 3 4
Mathematics
1 answer:
galina1969 [7]3 years ago
6 0
Remember that a quadratic equation is a parabola. The equation is of the type y = Ax^2 + Bx + C


A linear equation is a straight line. The equation is of the type y = MX + N


The soluction of that system is Ax^2 + Bx + C = MX + N

=> Ax^2 + (B-M)x + (C-N) = 0


That is a quadratic equation.


A quadratic equation may have 0, 1 or 2 real solutions. Those are all the possibilitis.


So you must select 0, 1 and 2.


You can also get to that conclusion if you draw a parabola and figure out now many point of it you can intersect with a straight line.


You will realize that depending of the straight line position it can intersect the parabola in none point, or one point or two points.  
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wel

To do this question you can use proportions.

3/60 is simplified to 1/20.

This shows that if you study 1 hour you get a 20. So to find the answer you multiply each side by 4.5, this means that if you study 4.5 hours you get a 90.

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3 years ago
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IrinaVladis [17]

Answer:

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BRAINLIST AND 30 POINTS
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