How many solutions are possible for a system of equations containing exactly one linear and one quadratic equation? (Select all
that apply). 0 1 2 3 4
1 answer:
Remember that a quadratic equation is a parabola. The equation is of the type y = Ax^2 + Bx + C
A linear equation is a straight line. The equation is of the type y = MX + N
The soluction of that system is Ax^2 + Bx + C = MX + N
=> Ax^2 + (B-M)x + (C-N) = 0
That is a quadratic equation.
A quadratic equation may have 0, 1 or 2 real solutions. Those are all the possibilitis.
So you must select 0, 1 and 2.
You can also get to that conclusion if you draw a parabola and figure out now many point of it you can intersect with a straight line.
You will realize that depending of the straight line position it can intersect the parabola in none point, or one point or two points.
You might be interested in
Answer:
growth
Step-by-step explanation:
5 is a positive number greater than 0 (not a decimal) making this growth
Answer:
for the lazy anti social people
Answer:

Use the ! tool to find the # of combinations.
8!/5! = 40,320/120 = 336