Answer:
For a trapezium of height H, parallel side 1 X, and parallel side 2 Y, the area is:
A = (1/2)*H*(X + Y)
with this we can complete the table.
a)
Here we know:
X = 7cm
Y = 11cm
H = 6cm
Then: A = (1/2)*6cm*(7cm + 11cm) = 54 cm^2
b)
Here we know:
X = 8 m
Y = 10 m
A = 126 m^2
Then:
126 m^2 = 0.5*H*(8m + 10m)
126 m^2 = H*9m
126 m^2/9m = H = 14m
Then the height of this trapezoid is 14m
c)
Here we know:
X = 5mm
H = 8mm
A = 72 mm^2
Then:
72 mm^2 = 0.5*8mm*(5mm + Y)
72 mm^2 = 4mm*(5mm + Y)
72mm^2/4mm = 5mm + Y
18 mm = 5mm + Y
18mm - 5mm = Y
13 mm = Y
Then the parallel side 2 is 13 mm long.
The equation of a circle with center (h, k) and radius r is
(x - h)^2 + (y - k)^2 = r^2
A diameter of 18 means a radius of 9.
(x + 3)^2 + (y - 5)^2 = 81
9514 1404 393
Answer:
11.7
Step-by-step explanation:
GeoGebra can not only draw the picture, it can answer the question. The approximate distance between the points is about 11.7 units.
__
The distance formula is used for this:
d = √((x1 -x1)² +(y2 -y1)²)
d = √((-4-2)² +(-3-7)²) = √(36 +100)
d = √136 ≈ 11.7
_____
Once you find that the distance is about √136, you know it is more than 11 (11² = 121) and less than 12 (12² = 144). The only answer choice that makes any sense is 11.7.
Answer:
alternate interior angles
Step-by-step explanation:
Answer:
Without an uploaded picture or further explanation, a valid answer can not be provided. My apologies