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Andrew [12]
3 years ago
12

Find the solution of 3 times the square root of the quantity of x plus 6 equals negative 12, and determine if it is an extraneou

s solution.
Mathematics
1 answer:
Anna35 [415]3 years ago
6 0
For this case we have the following equation:
 3 \sqrt{x+6}=-12
 Rewriting we have:
 \sqrt{x+6}= \frac{-12}{3}
 \sqrt{x+6}=-4
 We raise both members of the equation to the square:
 (\sqrt{x+6})^2=(-4)^2
 Rewriting we have:
 x+6=16
 x=16-6
 x=10
 It's a extraneous solution because equality is not met by substituting x = 10 in the original equation:
 3 \sqrt{10+6}=-12
 3 \sqrt{16}=-12
 3(4)=-12
 12=-12
 Answer:
 
The solution is:
 
x=10
 It's a extraneous solution

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