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pentagon [3]
3 years ago
9

Alex collects stamps. He wants to buy a superhero set for $3.88, a president set for $5.88, and a dinosaur set for $3.88. He has

$15 to spend on stamps. Which statement best describes whether an exact total or an approximate total should be calculated? A. Alex must add the 3 amounts exactly so he will know if he has enough money to buy the stamps. B. Alex can round the prices of the stamps to the nearest dollar and then add to estimate if he has enough money.
Mathematics
2 answers:
Anuta_ua [19.1K]3 years ago
6 0
The answer is B because the prices are close enough to the next dollar that it would be too high of an estimate to round up
ohaa [14]3 years ago
4 0

Answer:

b. alex can round the prices of the stamps to the nearest dollar and then add to estimate if he has enough money.

Step-by-step explanation:

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Step-by-step explanation:

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6 0
2 years ago
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Which of these is true<br> a: 0.7 &gt; 3/5 <br> b: 0.7 &lt; 3/5 <br> c: 0.7 = 3/5
omeli [17]
The answer is A. When 0.7 is put into fraction form it turns into 7/10. Then change the denominator of 3/5 to 10 which makes it 6/10. 7/10 is higher than 6/10 so the answer is A.
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3 years ago
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What are the next 5 numbers on the following sequence 0, 3, 8, 15, 24
son4ous [18]

Answer:

35, 48 63 80 99

Step-by-step explanation:

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1 year ago
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&gt;
olga nikolaevna [1]

Answer:5

Step-by-step explanation:>

Which exponential function is represented by the

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7

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o f(x) = 2( 3 )

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61,0.25) 17

7605

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1 2 3 4

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6 0
2 years ago
Help with Algebra 2: 1. <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B7%5D%7Bx%5E5%7D%20%7D%7B%5Csqrt%5B4%5D%7Bx%5E2%7D%
Mars2501 [29]

Answer:

See explanation

Step-by-step explanation:

1. Given the expression

\dfrac{\sqrt[7]{x^5} }{\sqrt[4]{x^2} }

Note that

\sqrt[7]{x^5}=x^{\frac{5}{7}} \\ \\\sqrt[4]{x^2}=x^{\frac{2}{4}}=x^{\frac{1}{2}}

When dividing \sqrt[7]{x^5} by \sqrt[4]{x^2}, we have to subtract powers (we cannot subtract 4 from 7, because then we get another expression), so

\dfrac{5}{7}-\dfrac{2}{4}=\dfrac{5}{7}-\dfrac{1}{2}=\dfrac{5\cdot 2-1\cdot 7}{14}=\dfrac{3}{14}

and the result is x^{\frac{3}{14}}=\sqrt[14]{x^3}

2. Given equation 3\sqrt[4]{(x-2)^3} -4=20

Add 4:

3\sqrt[4]{(x-2)^3} -4+4=20+4\\ \\3\sqrt[4]{(x-2)^3}=24

Divide by 3:

\sqrt[4]{(x-2)^3} =8

Rewrite the equation as:

(x-2)^{\frac{3}{4}}=8\\ \\(x-2)^{\frac{3}{4}}=2^3

Hence,

\left((x-2)^{\frac{3}{4}}\right)^{\frac{4}{3}}=(2^3)^{\frac{4}{3}}\\ \\x-2=2^{3\cdot \frac{4}{3}}\\ \\x-2=2^4\\ \\x-2=16\\ \\x-2+2=16+2\\ \\x=18

3 0
3 years ago
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