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monitta
3 years ago
11

Please do this i will give brainlieast and will give 75 points. go to this and and enter the right stuff!

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
4 0

I'll take a look at it.

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Write an expression in simplest form for the area of this shape.
Vitek1552 [10]

Answer:

x-4+(x-3)x This is the answer, if you don't understand, you can ask

Step-by-step explanation:

4 0
3 years ago
Label each statement as true or false regarding the zeros/roots of a quadratic function. The roots zeros of a quadratic function
ikadub [295]

Answer:

True, false, true, true.

Step-by-step explanation:

The roots zeros of a quadratic function are the same as the factors of the quadratic function. This is true because your roots are your factors—>(x-3) is a factor, x=3 is the root.

The roots zeros are the spots where the quadratic function intersects with the y-axis. No! Those are called y-intercepts!

The roots zeros are the spots where the quadratic function intersects with the x-axis. True. X-intercepts are your solutions. (x-3) graphed would the (3,0). That’s a solution.

There are not always two roots/zeros of a quadratic function,​ True. No solution would be when your quadratic doesn’t intersect the x-axis. One solution would be when your vertex would be on the x-axis. Two solutions is when your quadratic intersects the x-axis twice. Can there be infinite solutions? No. It’s either 0, 1, or 2 solutions.

6 0
2 years ago
Bgdfgfdgfbkbfkbbofgbbgr
Gemiola [76]

Answer:

Coolio, How are you

Step-by-step explanation:

3 0
2 years ago
The logarithm of a number to the base V2 is k. What is its logarithm to the base 2v2 ?​
kakasveta [241]

Answer:

log_{2\sqrt 2} X = \frac{1}{3}k

Step-by-step explanation:

Given

Let the number be X

From the first statement, we have:

log_{\sqrt 2} X = k

Required

Find log_{2\sqrt 2} X

log_{\sqrt 2} X = k

using the following law of logarithm

log_ab = n, b=a^n

So:

log_{\sqrt 2} X = k

X = \sqrt{2}^k

Substitute: X = \sqrt{2}^k in log_{2\sqrt 2} X

log_{2\sqrt 2} X = log_{2\sqrt 2} ( \sqrt{2}^k)

log_{2\sqrt 2} X = klog_{2\sqrt 2} \sqrt{2}

Apply the following law:

log_ab = \frac{log\ b}{log\ a}

log_{2\sqrt 2} X = k\frac{log\ \sqrt 2}{log\ {2\sqrt 2}}

Express the square roots as power

log_{2\sqrt 2} X = k\frac{log\ 2^\frac{1}{2}}{log\ {2 * 2^\frac{1}{2}}}

log_{2\sqrt 2} X = k\frac{log\ 2^\frac{1}{2}}{log\ {2^\frac{3}{2}}}

using the following law of logarithm

log_ab = n, b=a^n

log_{2\sqrt 2} X = k\frac{\frac{1}{2}log\ 2}{\frac{3}{2}log\ 2}}

log_{2\sqrt 2} X = k\frac{\frac{1}{2}}{\frac{3}{2}}}

Rewrite as:

log_{2\sqrt 2} X = k * \frac{1}{2} \div\frac{3}{2}

log_{2\sqrt 2} X = k * \frac{1}{2} *\frac{2}{3}

log_{2\sqrt 2} X = k * \frac{1}{1} *\frac{1}{3}

log_{2\sqrt 2} X = \frac{1}{3}k

4 0
2 years ago
Help me please please
vladimir2022 [97]

Answer:

a. 45 + 20x

   30 + 26x

b. 2.5 hours

c. 95

Step-by-step explanation:

45 + 20x = 30 + 26x

subtract 30 from both sides of the equation

15 + 20x = 26x

subtract 20x from both sides of the equation

15 = 6x

divide 6x on both sides of the equation

2.5 = x

7 0
3 years ago
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