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Ilya [14]
3 years ago
9

What is the area of the figure Enter your answer in the box __in2

Mathematics
2 answers:
iVinArrow [24]3 years ago
8 0
This is the area of a triangle and a square
Area of a triangle is 1/2BH
here total height is 16 in  triangle h is 16-10=6
base is 10
A=1/2*10*6
A=30 inch^2

Area of square=a^2
A2=10^2=100inches^2
A1+A2=100+30
130inches^2

kicyunya [14]3 years ago
7 0

Answer:

A_{total}=112in^{2}

Step-by-step explanation:

The given figure is formed by a right rectangle and a square.

By given, the dimensions of the square is 10 inches by 10 inches..

So, to find the dimensions of the right triangle, we just need to subtract.

The height of the right triangle would be

h=16in-10in=6in

Because the total length combined is 16 inches, and the side of the square is 10 inches. So, by subtraction, we find the height of the right triangle.

Applying the same reasoning, we find the base of the triangle

b=10in-6in=4in

Now, we are able to find both areas.

A_{triangle}=\frac{bh}{2}=\frac{4(6)}{2}=12in^{2}

A_{square}=(10in)^{2}=100in^{2}

Therefore, the whole are is the sum of each figure

A_{total}=A_{triangle} +A_{square} =12in^{2} +100in^{2} =112in^{2}

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First, simplify the expression 2r^2 + 3s^3 - r^2 + 4t^2 - r^2. Here you have three terms with r^2, group them in the following way:

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3 0
3 years ago
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1 year ago
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