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Sindrei [870]
3 years ago
11

Need help on this question

Mathematics
1 answer:
MariettaO [177]3 years ago
6 0

<u>Given:</u>

The two equations are 2x-5y=-7 and 5x-3y=11

We need to solve the equations using elimination method.

<u>Elimination method:</u>

Let us multiply the equation 2x-5y=-7 by 5, we get;

10x-25y=-35 ---------(1)

Now, multiplying the equation 5x-3y=11 by -2, we get;

-10x+6y=-22 --------(2)

Adding equations (1) and (2), we have;

\ \ \ 10x-25y=-35\\-10x+\ \ 6y=-22\\---------\\-19y=-57

      y=3

Thus, the value of y is 3.

Substituting y=3 in the equation 2x-5y=-7, we have;

2x-5(3)=-7

  2x-15=-7

          2x=8

            x=4

Thus, the value of x is 4.

Hence, the solution of the system of equations is (4,3)

Therefore, Option A is the correct answer.

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3 years ago
1. (Sec. 6.1) In a random sample of 80 components of a certain type, 12 are found to be defective. (a) Give a point estimate for
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(b) 0.7225

Step-by-step explanation:

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(b) Assuming that the sample is large enough to accurately provide a point estimate for the whole population, this can be treated as a binomial model with probability of success (non-defective part) p = 0.85. Since both components must be non-defective for the system to work, the probability of two successes in two trials is:

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