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Tomtit [17]
3 years ago
9

Whixh statement is true about the graphs of the functions shown below?

Mathematics
1 answer:
Nata [24]3 years ago
8 0

Answer:

Step-by-step explanation:

Since G(0) = g(0) = 20, the parabolic graphs of these functions share a y-intercept:  (0, 20).

Completing the square puts these equations into vertex form, which simplifies comparisons of the graphs:

G(x) = 2x^2 - 12x + 20 becomes

          2(x^2 - 6x + 9 - 9) + 20, or

          2(x - 3)^2 - 18 + 20, or 2(x - 3)^2 + 2.  Comparing this result to

          a(x - h)^2 + k, we see that the vertex is located at (3, 2).

Going through the same process for g(x) 2x^2+12x+20, we get:

g(x) = 2(x + 3)^2 + 2, whose vertex is at (-3, 2).

Next time, please include ALL info pertaining to your question, including the set of possible answer choices.  Thank you.

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kondor19780726 [428]

<u>Answer</u>

y = (1/2)x - 1


<u>Explanation</u>

The first step is to get the gradient of the line.

The two points in the line are; (2,0) and (-2, -2).

Gradient = (-2 - 0)/(-2, - 2)

                = -2/-4

                 = 1/2

To get the function we use one of the point (2,0) and a general point (x,y).

1/2 = (y - 0)/(x - 2)

1/2 = y/(x - 2)

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2y = x - 2

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3 years ago
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Tems11 [23]
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The Final answer is
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Sonbull [250]
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4 years ago
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Step-by-step explanation:

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Such a line has a slope of 0, so could be written in "slope-intercept form" as ...

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Answer:

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Step-by-step explanation:

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3 years ago
Read 2 more answers
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