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sweet-ann [11.9K]
3 years ago
7

Given: ∆DEK, DE = EK

Mathematics
1 answer:
Hunter-Best [27]3 years ago
4 0
DFE=46
kf=8

because ef is bisector that means e is 44+44=88 since the triangle is isosceles the other angles are equal 180-88=92 so each angle is 46. since 46+44=90 the smaller triangle def and efk are right. so I think that makes ef the perp bisector so that de=FM so kf=1/2dk.
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Which expression is equal to f(x)/g(x)
Pani-rosa [81]

Answer: i'd say c

Step-by-step explanation:

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Vanessa draws one side of equilateral ΔABC on the coordinate plane at points A(–2, 1) and B(4,1). What are the possible coordina
grandymaker [24]

Important question. No menu of choices given so we'll just have to figure it out.

It's not possible in two dimensions for all three vertices of an equilateral triangle to be lattice points, i.e. points with integer coordinates.  

Since A(-2,1) and B(4,1) have integer coordinates, our other point won't. There will be a √3 involved, the algebraic tell that there's a 30/60/90 triangle lurking somewhere in the problem.

Here the given side is parallel to the x axis which makes things easier.  

|AB| = 4 - -2 = 6

The x coordinate of the third vertex will be the same as that of the midpoint of AB, let's call it M,

M = ( (-2 + 4) / 2, (1 + 1)/2 ) = (1, 1)

We're making some progress.  Whatever our height h is our two candidates for the third vertex C are (1, 1 ± h).

Since |AB|=6, we get |AB|=|BC|=|AC|=6 because it's an equilateral triangle.

The altitude CM bisects the triangle into 2 30/60/90 triangles.  Let's take one of them, AMC.  Angle AMC is a right angle, so we have a right triangle with legs |AM|=3 and |CM|=h, and hypotenuse |AC|=6. The Pythagorean Theorem tells us:

3² + h² = 6²

9 + h² = 36

h² = 27

h = 3√3

Answer: C is (1, 1 + 3√3) or (1, 1 - 3√3)

4 0
3 years ago
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bixtya [17]

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Step-by-step explanation:

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4 0
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solong [7]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
What is the elimination to this solution i think its b
Blababa [14]

EXPLANATION:

To get the solution of the simultaneous equation, using the elimination method:

We will have the following steps:

Step 1:

Write the two equations:

\begin{gathered} y=-\frac{1}{2}x+3 \\ y=-\frac{7}{2}x-3 \end{gathered}

Step2: Subtract the two equations:

\begin{gathered} y-y=-\frac{1}{2}x-(-\frac{7}{2}x)+3-(-3) \\ 0=-\frac{1}{2}x+\frac{7}{2}x+6 \\  \end{gathered}

Step 3: Simplify the expression

\begin{gathered} 0=3x+6 \\ 3x=-6 \\ x=-\frac{6}{3} \\ x=-2 \end{gathered}

Step 4: Substitute x=-2 into the formula:

\begin{gathered} y=-\frac{1}{2}x+3 \\ y=-\frac{1}{2}\times-2+3 \\ y=1+3 \\ y=4 \end{gathered}

Therefore, the answer is

(-2,4)

Thus,

Option B is correct

5 0
1 year ago
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