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nevsk [136]
3 years ago
11

At a particular restaurant, each chicken wing has 75 calories and each slider has 250 calories. A combination meal with chicken

wings and sliders is shown to have 800 total calories and twice as many chicken wings as there are sliders. Write a system of equations that could be used to determine the number of chicken wings in the combination meal and the number of sliders in the combination meal. Define the variables that you use to write the system.
Mathematics
1 answer:
VikaD [51]3 years ago
8 0

Know a are:

CW=75. SL= 250. Y= 2x

CW= X= number of wings

SL= Y= number of sliders

X+Y= Total number of items, which can be rewritten as X+2X= total

Plug in the calories for the total

2(75X) +250X= 800

150x+250X= 400X= 800

X= 800/400=2 pieces of Slider

Double the amount for Wings=2x2=4

4wings/2 Sliders

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Gnom [1K]

Answer:

It is a better deal to do the 6.50 for 12 ounces

Step-by-step explanation:

The reason is because the is 16 ounces in a pound so you would do 8.99/16 and you get .56 per ounce but is you do 6.50/12 you get .54 per ounce which is a better deal.

Hope this helped!!

3 0
3 years ago
What number can you use to simplify 5 and 15?
pshichka [43]

Answer:

You can use 5 to simplify 5 and 15, giving you 1 and 3

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7 0
3 years ago
Which is bigger 7.79 or .99
lord [1]
7.79 is larger than .99
6 0
4 years ago
Read 2 more answers
The volume of the cell phone is 75 cubic centimeters. Write and solve an equation to find the height of the cell phone. Round yo
prohojiy [21]

Answer:

Equation: Height = \frac{75}{Area}

Step-by-step explanation:

<em>The question is incomplete as the dimension of the phone was not given.</em>

<em>However, the following explanation will guide you</em>

Given

Volume = 75\ in^3

Required

Determine the Height

Volume is calculated as thus;

Volume = Area * Height

Substitute 75 for Volume

75= Area * Height

Divide through by Area

Height = \frac{75}{Area}

<em>The above represent the equation to solve for Height</em>

<em>To solve for height, we need the dimension of the phone or the area.</em>

Take for instance; the length and width of the phone is 5 by 5 inches;

The height would be:

Height = \frac{75}{5 * 5}

Height = \frac{75}{25}

Height = 3\ inches

5 0
3 years ago
Strain-displacement relationship) Consider a unit cube of a solid occupying the region 0 ≤ x ≤ 1, 0 ≤ y ≤ 1, 0 ≤ z ≤ 1 After loa
Anastasy [175]

Answer:

please see answers are as in the explanation.

Step-by-step explanation:

As from the data of complete question,

0\leq x\leq 1\\0\leq y\leq 1\\0\leq z\leq 1\\u= \alpha x\\v=\beta y\\w=0

The question also has 3 parts given as

<em>Part a: Sketch the deformed shape for α=0.03, β=-0.01 .</em>

Solution

As w is 0 so the deflection is only in the x and y plane and thus can be sketched in xy plane.

the new points are calculated as follows

Point A(x=0,y=0)

Point A'(x+<em>α</em><em>x,y+</em><em>β</em><em>y) </em>

Point A'(0+<em>(0.03)</em><em>(0),0+</em><em>(-0.01)</em><em>(0))</em>

Point A'(0<em>,0)</em>

Point B(x=1,y=0)

Point B'(x+<em>α</em><em>x,y+</em><em>β</em><em>y) </em>

Point B'(1+<em>(0.03)</em><em>(1),0+</em><em>(-0.01)</em><em>(0))</em>

Point <em>B</em>'(1.03<em>,0)</em>

Point C(x=1,y=1)

Point C'(x+<em>α</em><em>x,y+</em><em>β</em><em>y) </em>

Point C'(1+<em>(0.03)</em><em>(1),1+</em><em>(-0.01)</em><em>(1))</em>

Point <em>C</em>'(1.03<em>,0.99)</em>

Point D(x=0,y=1)

Point D'(x+<em>α</em><em>x,y+</em><em>β</em><em>y) </em>

Point D'(0+<em>(0.03)</em><em>(0),1+</em><em>(-0.01)</em><em>(1))</em>

Point <em>D</em>'(0<em>,0.99)</em>

So the new points are A'(0,0), B'(1.03,0), C'(1.03,0.99) and D'(0,0.99)

The plot is attached with the solution.

<em>Part b: Calculate the six strain components.</em>

Solution

Normal Strain Components

                             \epsilon_{xx}=\frac{\partial u}{\partial x}=\frac{\partial (\alpha x)}{\partial x}=\alpha =0.03\\\epsilon_{yy}=\frac{\partial v}{\partial y}=\frac{\partial ( \beta y)}{\partial y}=\beta =-0.01\\\epsilon_{zz}=\frac{\partial w}{\partial z}=\frac{\partial (0)}{\partial z}=0\\

Shear Strain Components

                             \gamma_{xy}=\gamma_{yx}=\frac{\partial u}{\partial y}+\frac{\partial v}{\partial x}=0\\\gamma_{xz}=\gamma_{zx}=\frac{\partial u}{\partial z}+\frac{\partial w}{\partial x}=0\\\gamma_{yz}=\gamma_{zy}=\frac{\partial w}{\partial y}+\frac{\partial v}{\partial z}=0

Part c: <em>Find the volume change</em>

<em></em>\Delta V=(1.03 \times 0.99 \times 1)-(1 \times 1 \times 1)\\\Delta V=(1.0197)-(1)\\\Delta V=0.0197\\<em></em>

<em>Also the change in volume is 0.0197</em>

For the unit cube, the change in terms of strains is given as

             \Delta V={V_0}[(1+\epsilon_{xx})]\times[(1+\epsilon_{yy})]\times [(1+\epsilon_{zz})]-[1 \times 1 \times 1]\\\Delta V={V_0}[1+\epsilon_{xx}+\epsilon_{yy}+\epsilon_{zz}+\epsilon_{xx}\epsilon_{yy}+\epsilon_{xx}\epsilon_{zz}+\epsilon_{yy}\epsilon_{zz}+\epsilon_{xx}\epsilon_{yy}\epsilon_{zz}-1]\\\Delta V={V_0}[\epsilon_{xx}+\epsilon_{yy}+\epsilon_{zz}]\\

As the strain values are small second and higher order values are ignored so

                                      \Delta V\approx {V_0}[\epsilon_{xx}+\epsilon_{yy}+\epsilon_{zz}]\\ \Delta V\approx [\epsilon_{xx}+\epsilon_{yy}+\epsilon_{zz}]\\

As the initial volume of cube is unitary so this result can be proved.

5 0
3 years ago
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