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wel
3 years ago
11

Need answer ASAP!!!!!!!!!

Mathematics
1 answer:
seropon [69]3 years ago
3 0
The answer would be x= 7,-7
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Binomials: Expand (2a+3)^3 (PLEASE ANSWER QUICKLY)
hodyreva [135]

Answer:

8 {a}^{3}  +  {36a}^{2} +  54a + 27 \\

Explanation:

Binomial theorem,

{(p + q)}^{3}  =  {p}^{3}  + 3 {p}^{2} q +  {q}^{3}

4 0
2 years ago
A share of stock in the Lofty Cheese Company is quoted at 25 1/4. Suppose you hold 30 shares of that stock, which you bought at
Marizza181 [45]
I don't know the options, but I can say this:

if you bought it at 20 1/4 and you sell them at 25 1/4 then your win pro stock is the difference between those two numbers, which is 5. (25 1/4-20 1/4 =5)

and if you sell all of them, your profit will be 30*5=150 dollars.
6 0
4 years ago
Ford and GM pick up trucks are being tested for fuel efficiency, which is commonly measured in miles per gallon (mpg). The fuel
lina2011 [118]

Answer:

0.7881 = 78.81% probability that a randomly chosen Ford truck outperforms a randomly chosen GM truck in terms of fuel efficiency

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Subtraction of normal variables:

When we subtract normal variables, the mean is the subtraction of the means, and the standard deviation is the square root of the sum of the variances.

The fuel efficiency of Ford trucks is found to follow a normal distribution with mean 20 mpg and a standard deviation of 3 mpg.

This means that \mu_{F} = 20, \sigma_{F} = 3

The fuel efficiency of GM trucks is found to follow a normal distribution with mean 24 mpg and standard deviation of 4 mpg.

This means that \mu_{G} = 24, \sigma_{G} = 4

Compute the probability that a randomly chosen Ford truck outperforms a randomly chosen GM truck in terms of fuel efficiency

This is the probability that the subtraction of ford by gm is less than 0. First, we find the mean and the standard deviation.

\mu = \mu_{F} - \mu_{G} = 20 - 24 = -4

\sigma = \sqrt{\sigma_{F}^2+\sigma_{G}^2} = \sqrt{3^2+4^2} = 5

This probability is the pvalue of Z when X = 0. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{0 - (-4)}{5}

Z = 0.8

Z = 0.8 has a pvalue of 0.7881

0.7881 = 78.81% probability that a randomly chosen Ford truck outperforms a randomly chosen GM truck in terms of fuel efficiency

7 0
3 years ago
Pls help me I will mark as brilliant​
Marina CMI [18]

Answer:

2a+7 2a+4

2a-1 2a+b-3

2a-b-1 2a

4 0
2 years ago
Determine if true:<br> 24+24-8x2=80
Savatey [412]
Answer:true

Explanation:
24+24=48
48-8=40
40x2=80
80=80!

So it is true.
5 0
2 years ago
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