Answer:
All points on line CD are equidistant from A and B
Step-by-step explanation:
Given that point A is the center of circle A and point B is the center of circle B, and the circumference of circle A passes through the center of circle B which is point B and vice versa.
Therefore we have;
The radius of circle A = The radius of circle B
Which gives;
The distance of the point C to the center A is equal to the distance of the point C to the center B
Similarly, the distance of the point D to the center A is equal to the distance of the point D to the center B
So also the distances of all points on the line from the center A is equal to the distances of all points on the line from the center B.
Answer:
Whats the X given for this problem? ex.... X = 6 and the problem is:
2x (>) or (<) or = to 13
substitute ( x = 6 ) in 2x and you get 12 is < 13.
Answer:
The desired expression is 19 x (3 tens) = 19 x 30 = 570
So, the greatest ten = 3 (tens)
Step-by-step explanation:
Let us check each tens.
19 x (1 ten) = 19 x 10 = 190
19 x (2 tens) = 19 x 20 = 380
19 x (3 tens) = 19 x 30 = 570
19 x (4 tens) = 19 x 40 = 760
But, here 760 is OVER the given term 684.
and 570 is the nearest value to the value 684.
So, the desired expression is 19 x (3 tens) = 19 x 30 = 570
25= 1.50x+4
Subtract 4
21= 1.50x
Divide by 1.50
X=14 rides or less
