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gladu [14]
3 years ago
8

WILL GIVE BRAINLIEST FOR BEST ANSWER NO LINKS!!!!*Use the data from the dot plot below to answer the question. The data shows ga

mes of a soccer season and the number of goals scored in each game.
Which goals were scored the fewest amount of times during the soccer season?





Question 5 options:


3



0, 7



1, 4, 5, 6



2

Mathematics
1 answer:
Ganezh [65]3 years ago
6 0

0, 7

0 and 7 have the least amount of dots.

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Simplify the expression and show your work. 4y+5=-31
kondor19780726 [428]
4y +5=-31 \\ 
4y+5-5 = 31-5 \\ 
4y=-36 \\ 
4y/4=-36/4 \\ 
y=-9 \\ 
Check: \\ 
4(-9)+5=-31 \\ 
-36+5=-31 \\ 
-31=-31
3 0
3 years ago
Find lim x→3 sqrt 2x+3-sqrt 3x/ x^2-3x. you must show your work or explain your work in words plsss I need help
sineoko [7]

I'm assuming the limit is supposed to be

\displaystyle\lim_{x\to3}\frac{\sqrt{2x+3}-\sqrt{3x}}{x^2-3x}

Multiply the numerator by its conjugate, and do the same with the denominator:

\left(\sqrt{2x+3}-\sqrt{3x}\right)\left(\sqrt{2x+3}+\sqrt{3x}\right)=\left(\sqrt{2x+3}\right)^2-\left(\sqrt{3x}\right)^2=-(x-3)

so that in the limit, we have

\displaystyle\lim_{x\to3}\frac{-(x-3)}{(x^2-3x)\left(\sqrt{2x+3}+\sqrt{3x}\right)}

Factorize the first term in the denominator as

x^2-3x=x(x-3)

The x-3 terms cancel, leaving you with

\displaystyle\lim_{x\to3}\frac{-1}{x\left(\sqrt{2x+3}+\sqrt{3x}\right)}

and the limand is continuous at x=3, so we can substitute it to find the limit has a value of -1/18.

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3 years ago
What is the value of x? Enter your answer in the box. x=
SOVA2 [1]
48 degrees, anything opposite of a degree on the same 2 infinite lines will always be the degree.
8 0
3 years ago
Jane buys some rocks for decorating her backyard. She uses a box full of rocks. The box is a rectangular container that is 1 yar
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4 0
3 years ago
Can y’all help me please !
Leviafan [203]

no because she turned it only 90 degrees not 180.

180 would be a mirror reflection

6 0
3 years ago
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