Answer:
For this case if we want to conclude that the sample does not come from a normally distributed population we need to satisfy the condition that the sample size would be large enough in order to use the central limit theoream and approximate the sample mean with the following distribution:
For this case the condition required in order to consider a sample size large is that n>30, then the best solution would be:
n>= 30
Step-by-step explanation:
For this case if we want to conclude that the sample does not come from a normally distributed population we need to satisfy the condition that the sample size would be large enough in order to use the central limit theoream and approximate the sample mean with the following distribution:
For this case the condition required in order to consider a sample size large is that n>30, then the best solution would be:
n>= 30
<h2>The graph of y = ax^2 + bx + c
</h2><h2>A nonlinear function that can be written on the standard form
</h2><h2>ax2+bx+c,where a≠0
</h2><h2>All quadratic functions has a U-shaped graph called a parabola. The parent quadratic function is
</h2><h2>
y=x2
</h2><h2>
The lowest or the highest point on a parabola is called the vertex. The vertex has the x-coordinate
</h2><h2>x=−b2a
</h2><h2>The y-coordinate of the vertex is the maximum or minimum value of the function.
</h2><h2>a > 0 parabola opens up minimum value
</h2><h2>a < 0 parabola opens down maximum value
</h2><h2>
A rule of thumb reminds us that when we have a positive symbol before x2 we get a happy expression on the graph and a negative symbol renders a sad expression.
</h2><h2>The vertical line that passes through the vertex and divides the parabola in two is called the axis of symmetry. The axis of symmetry has the equation
</h2><h2>x=−b2a
</h2><h2>The y-intercept of the equation is c.
</h2><h2>
When you want to graph a quadratic function you begin by making a table of values for some values of your function and then plot those values in a coordinate plane and draw a smooth curve through the points.</h2>
Answer:
c.) aₙ = 5 × 4ⁿ⁻¹
Explanation:
Geometric sequence: aₙ = a(r)ⁿ⁻¹
where 'a' resembles first term of a sequence, 'r' is the common difference.
Here sequence: 5, 20, 80, 320,...
First term (a) = 5
Common difference (d) = second term ÷ first term = 20 ÷ 5 = 4
Hence putting into equation: aₙ = 5(4)ⁿ⁻¹
