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satela [25.4K]
2 years ago
14

Twelve boxes of pencils cost $16. Which equation could you use to find the cost per box

Mathematics
2 answers:
zheka24 [161]2 years ago
3 0

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

                  Hello!

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

❖ You can use the equation 16 ÷ 12 = 1.33

~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡

~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

DanielleElmas [232]2 years ago
3 0

Answer:

$1.33 per box

Step-by-step explanation:

To find the cost per box, take the total cost and divide by the number of boxes.

$16/12 boxes

$1.33 per box

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olganol [36]

Answer:

24

Step-by-step explanation:

what is the smallest number which is a multiple of both 8 and 12? so, an multiple of 8 must have 2 as a factor at least 3 times. Similarly, multiples of 12 have at least two 2's and one 3. so we need 2x2x2x3 or 24 if every factor is to be included.

I'm not the best at explaining but you can search google to get the better Idea.

(btw this is for the fist question)

6 0
3 years ago
I need the answer please will mark brainliest
Flura [38]

Answer:

Look below.

Step-by-step explanation:

For further reference I suggest looking at Khan academy videos of this.

A. log8 5/9

B. log9 4

C. log6 2^3

7 0
3 years ago
Read 2 more answers
A commonly used unit of mass in the English system is the pound-mass, abbreviated lbm, where 1 lbm = 0.454 kg. What is the densi
Rashid [163]
<h2>Density of ethyl alcohol is 56.25 lbm/ft³ </h2>

Step-by-step explanation:

We have 1 lbm = 0.454 kg

1 kg = 2.203 lbm

1 m = 3.28 ft

Density of ethyl alcohol = 9.01 x 10² kg/m³

\texttt{Density = }\frac{9.01\times 10^2\times 2.203}{3.28^3}=56.25lbm/ft^3

So

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3 0
3 years ago
What is the mode of the following set of data? 34, 23, 12, 11, 11, 25, 25, 26, 25, 27, 30
Olin [163]
1 - B

Mode - The mode the number that appears most often in a data set. In this question, 25 was repeated 3 times and no other ones where repeated 3 times. Thats why 25 is the mode.

2 - D

Median - The middle number of a data set that is arranged from least to greatest.

3 - True

There is no mode because all of the numbers only appear once.

4 - A

5 - C

4 0
3 years ago
Garne Problem med
Citrus2011 [14]

Total distance the rover need to travel ​is D = 1miles .

<u>Step-by-step explanation:</u>

We have , Garne Problem med   . A rover needs to travel mile to reach its destination  traveled mile. a rover needs to travel 5/8 mile to reach its destination it has already travel 3/8 miles . We need to find that  how much farther does the rover need to travel ​ , Let's do it step by step:

First , rover has already traveled 3/8 miles , Let total distance to be traveled by rover is D :

⇒ D = \frac{3}{8} + d , where d is distance left to cover .

Now, rover need to travel 5/8 miles more to reach destination :

⇒ D = \frac{3}{8} + d , where d is distance left to cover  , So d = \frac{5}{8}

⇒ D = \frac{3}{8} + d

⇒ D = \frac{3}{8} + \frac{5}{8}

⇒ D = \frac{3+5}{8}

⇒ D = \frac{8}{8}

⇒ D = 1miles

∴ Total distance the rover need to travel ​is D = 1miles .

8 0
3 years ago
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