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Aliun [14]
3 years ago
7

In a class, 45 students are taking the SAT exam.The number of boys is 9 more than the number of girls.How many girls and boys ar

e in the classroom?
Write a system of equations and solve using any method.
Mathematics
1 answer:
maxonik [38]3 years ago
7 0
The equation would be
g + (g + 9) = 45
2g + 9 = 45
- 9
2g = 36
÷ 2
g = 18
18 + 9 = 27
Girls: 18
Boys: 27
Hope this helps! Let me know if you have any questions :)
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Find all real numbers for which the rational expression is undefined. (Enter your answers as a comma-separated list. If no value
Marianna [84]

Answer: +9, -9

Step-by-step explanation: The rational expression in this case is undefined if the the denominator is equal to zero, which means that the x cannot be whatever makes the denominator zero, so:

x² - 81 = 0 ⇒ x² = 81 ⇒ x = +/- √81 ⇒ x = +/- 9

Note that we are using the equal sign just because this particular problem askes for a solutions that is undefined.

6 0
3 years ago
Select the value(s) that represent
Brut [27]

Answer:

its 6/7

Step-by-step explanation:

i hope this help

3 0
2 years ago
This skateboard ramp has two ladders. On ladder is 40 feet high and the other is 24 feet high. The distance from the top of the
Verizon [17]
Okay, so we know that the distance from the high ladder to the bottom is 200 feet... if you take 200/40 its 5 now take 24*5 and the answer should be 120
8 0
3 years ago
What are the first, second, and third frequencies audible from a 20 cm long organ pipe when (A) only one end is open and when (B
kotykmax [81]
A) The answers are:
the first frequency - 428.75 Hz
the second frequency - 1286.25 Hz
the third frequency - 2143.75 Hz

The frequency (when the pipe is closed) is: f = v(2n - 1)/4L
v - the speed of sound
n - the frequency order
L - the length of the organ pipe

We know:
v = 343 m/s
L = 20 cm = 0.2 m

1. The first frequency (n = 1):
f = 343 * (2 * 1 - 1) / 4 * 0.2 = 343 * 1 / 0.8 = 428.75 Hz


2. The second frequency (n = 2):
f = 343 * (2 * 2 - 1) / 4 * 0.2 = 343 * 3 / 0.8 = 1286.25 Hz


3. The third frequency (n = 3):
f = 343 * (2 * 3 - 1) / 4 * 0.2 = 343 * 5 / 0.8 = 2143.75 Hz


B) The answers are:

the first frequency - 857.5 Hz
the second frequency - 1715 Hz
the third frequency - 2572.5 Hz

The frequency (when the pipe is open) is: f = vn/2L
v - the speed of sound
n - the frequency order
L - the length of the organ pipe

We know:
v = 343 m/s
L = 20 cm = 0.2 m

1. The first frequency (n = 1):
f = 343 * 1 / 2 * 0.2 = 343 / 0.4 = 857.5 Hz


2. The second frequency (n = 2):
f = 343 * 2 / 2 * 0.2 = 686 / 0.4 = 1715 Hz


3. The third frequency (n = 3):
f = 343 * 3 / 2 * 0.2 = 1029 / 0.4 = 2572.5 Hz
4 0
3 years ago
Devin jumped off a cliff into the ocean in Acapulco while vacationing with his family. His height as a function of time could be
sukhopar [10]

Answer:

<em>3 seconds</em>

Step-by-step explanation:

Given the height modelled by the function

h(t) = -16t² + 16t + 96

The hit the water at h(t) = 0

0 = -16t² + 16t + 96

Divide through b y -16

0 = t² - t - 6

t² - t - 6 = 0

t² - 3t+2t - 6 = 0

t(t-3)+2(t-3) = 0

t+ 2 = 0 and t - 3 = 0

t = -2 secs and t = 3secs

Since t can't be negative, hence;

t = 3 secs

<em>hence it will take 3 seconds until Devon hit the water</em>

7 0
2 years ago
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