WILL GIVE BRAINLIEST 5 STARS AND THANKS Find the number of 4-digit numbers that contain exactly two even and two odd digits.
2 answers:
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Answer:
Step-by-step explanation:
So, in order to solve this problem, I started off by drawing it out. On my graph that I have attached below, I first started out by locating the points (-5,7) and (2,3). Now, this is an optional step, but I highly encourage practicing your graphing skills by solving this problem on graph paper as well. Next, I connected the two points that I just graphed. This is the line that passes through (-5,7) and (2,3).
Now, here is where the actual solving starts. If you haven't already been taught this yet, I will introduce it to you now. I am going to find the equation of this line by filling in what I know in the equation y=mx+b, where m= the slope of the line, and b= y intercept.
Slope of the line: m=
If you haven't been taught how to find the slope of a line I recommend you find out.
Substitute the slope into the equation.
Now, we will solve for the 'b,' or y intercept.
We already have x and y values to use: (-5,7) or (2,3). I'll use x=2 and y=3 to solve for the y intercept.
Last step: substitute the slope and y intercept into y=mx+b.
That is the answer to this problem.
I hope this helps.
