what is the equation, in slope-intercept form, of the line that is perpendicular to the line y – 4 = –2/3 (x – 6) and passes thr
ough the point (−2, −2)? y = –x – 10/3 y = –x 10/3 y = x – 1 y = x 1
1 answer:
For perpendicular lines, m2 = -1/m1 = -1/(-2/3) = 3/2 [m1 = -2/3]
Required equation is y + 2 = 3/2(x + 2) => y + 2 = 3/2 x + 3 => y = 3/2 x + 1
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