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storchak [24]
3 years ago
6

How many numbers in the list 43, 4343, 434343, ...., are prime?

Mathematics
1 answer:
Paraphin [41]3 years ago
8 0
The numbers 43 is the only prime number in the list.
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What is the solution to the system please help
IrinaVladis [17]

Answer:

(-\frac{50}{13},-\frac{12}{13})

Step-by-step explanation:

To start, you need to find the equation of both of these lines. For the orange one, the slope can be found with the points (-5,0) and (0,-4), where there is a drop of 4 for a run of 5. This is a slope of -4/5, and a y-intercept of -4. For the purple line, you can use the points (-2,0) and (0,1), where there is a rise of 1 for a run of 2 or a slope of 1/2 and a y intercept of 1. Therefore, the two equations are:

y=-\frac{4}{5}x-4

y=\frac{1}{2}x+1

You can now set them equal to each other:

-\frac{4}{5}x-4=\frac{1}{2}x+1

Add 4 to both sides:

-\frac{4}{5}x=\frac{1}{2}x+5

Multiply both sides by 2:

-\frac{8}{5}x=x+10

Multiply both sides by 5:

-8x=5x+50

Subtract 5x from both sides:

-13x=50

Divide both sides by -13:

x=-\frac{50}{13}

y=-\frac{12}{13}

Hope this helps!

7 0
3 years ago
Sasha has 3.20 in U.S. coins. She has the same number of quarters and nickels. What is the greatest number of quarters she could
RSB [31]

Answer:

10 quarters = $2.50

10 nickels = $0.50

that leaves $0.20 for other coins (dimes / pennies)

Step-by-step explanation:

First, suppose she has only quarters and nickels and no other coins.  Then if C is the identical number of coins of each type, then 5C + 25C = 320, so 30C = 320 and 3C = 32, but there is no integer solution to this.  So she must have at least one other type of coin.

Assume she has only quarters, nickels, and dimes.  Then if D is the number of dimes, 5C +  25C + 10D = 320, which means 30C + 10D = 320, or 3C + D = 32.  The smallest D can be is 2, leaving 3C = 30 and thus C = 10.  So in this scenario she would have 10 quarters, 10 nickels, and two dimes to make $2.50 + $0.50 + $0.20 = $3.20.

This has to be the highest number, because if she had 11 quarters and 11 nickels, that alone would add up to 11(0.25) + 11(0.05) = $3.30, which would already be too much.

8 0
3 years ago
Read 2 more answers
A woman has 7 keys. only one of them will open her door. when seh arrives at the door there is no sufficient light for her to fi
Gala2k [10]
Since she has seven key the probability that the first one will open the door is
\frac{1}{7}
if it takes three attempts to open the door,the probability is
\frac{1}{3}
if the three attempts would not work
then the probability that the fourth attempt will open the door is
\frac{1}{4}
hope this helps
7 0
3 years ago
Shane is using pieces of square paper to cover a cube shaped gift with sides that are 9 inches long to find out the area of the
nordsb [41]

Answer:

The area of the cube is 486 inches^2

Step-by-step explanation:

In this question, we are tasked with calculating the area of cube with side 9 inch.

Mathematically, the area can be calculated using the formula A = 6s^2

Now, what we need to do is to substitute 9 inches for s

Thus, A = 6 * 9^2

A = 6 * 81

A = 486 inches^2

3 0
3 years ago
The length of a rectangular garden is 8m greater than twice the width the area of the garden is 280m^2 what is the width of the
yarga [219]

Step-by-step explanation:

Given :-

The length of the garden 8m greater than 2 times the width.

Area of the garden is 280 m²

Let us consider the length as x and width as y.

Sp, we can day length as :-

x = 8 + 2y ---(1)

Now, we know that:-

Area of Rectangle = Length × Breadth

280 = x * y

We can replace the value of x now,

280 = y × ( 8 + 2y)

280 = 8y + 2y²

2y² + 8y - 280 = 0

y² + 4y - 140 = 0

Factorise it.

(y -10)(y + 14)

Cancelling -ve value, we get the width as 10 metres.

<u>Hope</u><u> </u><u>it</u><u> </u><u>helps</u><u> </u><u>:</u><u>)</u>

5 0
3 years ago
Read 2 more answers
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