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zheka24 [161]
3 years ago
5

I really need help on this can someone please help me ASAP???!!!?

Mathematics
2 answers:
Charra [1.4K]3 years ago
5 0

Answer:

They all have 90 degrees angles and they have the same width and height they are just on different sides

Step-by-step explanation:

WARRIOR [948]3 years ago
3 0

Dude What Kind Of Phone You Have?

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Find the equation of the linear function represented by the table below in slope-
pav-90 [236]

Answer: y=-3x-2

Step-by-step explanation:

Using the values x=-2, y=4 and x=1, y=-5, the slope is \frac{-5-4}{1-(-2)}=-3.

So, the equation is:

y-4=-3(x+2)\\\\y-4=-3x-6\\\\y=-3x-2

3 0
1 year ago
Cheryl has some oranges. she puts the oranges into p boxes of 3 oranges each and has 2 oranges left. Find the total number of or
Umnica [9.8K]
So she had x oranges

she put the oranges into p boxes with 3 in each box and had 2 left so

total=3 times p+2 or
total=3p+2
7 0
3 years ago
Read 2 more answers
Whats the answer for number 3
Karolina [17]

cant see the full question ;/

5 0
3 years ago
BRAINLIEST ASAP! PLEASE HELP ME :)
nikdorinn [45]

Answer:

m <1 = 61

Step-by-step explanation:

We know that the angle adjacent to 130 is 50 degrees because linear angles are complementary.

Extending line t to make a triangle, we can find the angle adjacent to the angle labeled 111  ( and above it) is 69.

That makes the angle that touches line q 61 to finish the triangle

This angle and angle 1 are corresponding angles, so they are equal

<1 = 61

7 0
3 years ago
Expand the given power using the Binomial Theorem. (10k – m)5
agasfer [191]

Answer:

(10k - m)^{5}=100000k-50000k^{4}m+10000k^{3}m^{2}-1000k^{2}m^{3}+50km^{4}-m^{5}

Step-by-step explanation:

* Lets explain how to solve the problem

- The rule of expand the binomial is:

(a+b)^{n}=(a)^{n}+nC1(a)^{n-1}(b)+nC2(a)^{n-2}(b)^{2}+nC3(a)^{n-3}(b)^{3}+...............+(b)^{5}

∵ The binomial is (10k-m)^{5}

∴ a = 10k , b = -m and n = 5

∴ (10k-m)^{5}=(10k)^{5}+5C1(10k)^{4}(-m)+5C2(10k)^{3}(-m)^{2}+5C3(10k)^{2}(-m)^{3}+5C4(10k)^{1} (-m)^{4}+5C5(10k)^{0}(-m)^{5}

∵ 5C1 = 5

∵ 5C2 = 10

∵ 5C3 = 10

∵ 5C4 = 5

∵ 5C5 = 1

∴ (10k-m)^{5}=100000k^{5}+(5)(10000)k^{4}(-m)+(10)(1000)k^{3}(m^{2})+(10)(100)k^{2}(-m^{3})+5(10k)^{1} (m^{4})+(10k)^{0}(-m^{5})

∴ (10k-m)^{5}=100000k^{5}-50000)k^{4}m+10000k^{3}m^{2}-1000k^{2}m^{3}+50km^{4}-m^{5}

5 0
3 years ago
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