Let area of triangle AEC = x
Area of triangle BAC = 1/2 * 15 * 12 = 90
Area of triangle DCA = 1/2 * 15 * 6 = 45
90 = p + x and
45 = q + x Subtracting the 2 equations:-
90 - 45 = p - q
Answer p - q = 45
Answer:
7.10299
Step-by-step explanation:
is best evaluated in a calc.
Okay if there are 8 teachers and 6 reams of paper you would have to divide 6 by 8 and you would get 0.75
6/8= 0.75
each teacher would get 0.75 (3/4) of a ream of paper
Answer: x=80°
Explanation:
To find the exterior angle x we first need to find the last corner angle (a) of the triangle. The angles of triangles add up to 180° so we can use the formula: 25+55+a=180
Solving formula:
25+55+a=180
80+a=180
(Subtract 80 from both sides)
a=100°
Now that we know a=100 we can find the exterior angle. a+x=180 because the angles are on a straight line which equals 180°
a+x=180
100+x=180
(Subtract 100 from both sides)
x=80°
Hope this helps! Please leave a thanks if possible so I can continue to help others :)
