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koban [17]
4 years ago
6

A submarine was 38 feet below sea level it dove 45 more and then ascended 30 feet what is the submarines current elevation

Mathematics
2 answers:
bearhunter [10]4 years ago
8 0
It is 53 feet below sea level.
daser333 [38]4 years ago
4 0

Answer:

'

''

Step-by-step explanation:

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Help Please ( and leave on how you solved it ) ":(<br> view pic below
Anton [14]

Answer:

The value of x = 10.

Step-by-step explanation:

From the given triangle,

  • The value of angle M = (3x + 28)°
  • The value of angle K = (5x - 18)°
  • The value of angle L = 90°

We know that the sum of a triangle is 180°.

i.e.

K + L + M = 180°

(5x - 18)° + 90° + (3x + 28)° = 180°

5x-18+90+3x+28=180

5x+3x-18+90+28=180

8x-18+90+28=180

8x+100=180

8x=80

\frac{8x}{8}=\frac{80}{8}

x=10

Therefore, the value of x = 10

8 0
3 years ago
Use the order of operations to simplify<br> 5*3 to the second power-15/5
ASHA 777 [7]

Assuming the question reads:

5 \cdot 3^2 - 15 \div 5

The order of operations is as follows:

Parentheses

Exponents

Multiplication/Division

Addition/Subtraction

There are no parentheses in the equation.

There is an exponent in the equation. Solve this term first:

3^2 = 9

The equation should now read:

5 \cdot 9 - 15 \div 5

There are two multiplication/division operations in the equation. Solve them individually:

5 \cdot 9 = 45

15 \div 5 = 3

The equation should now read:

45 - 3

There is one subtraction operation. Solve this term for your answer:

45 - 3 = \boxed{42}

7 0
3 years ago
8 times what equals 40
erica [24]
Eight times five equals forty.

The answer is 5.
4 0
3 years ago
Read 2 more answers
from an observer o, the angles of elevation of the bottom and the top of a flagpole are 40° and 45° respectively.find the height
maksim [4K]

Answer:

Take a look of the image below, we can think on this problem as a problem of two triangle rectangles.

We can see that both triangles share the adjacent cathetus, then the height of the flagpole is just the difference between the opposite cathetus.

Remember the relation:

Tan(a) = (opposite cathetus)/(adjacent cathetus)

So, if we define H as the height of the cliff

X as the distance between the observer and the cliff

and h as the height of the flagopole

we can write:

tan(40°) = H/X

tan(45°) = (H + h)/X

Notice that we have two equations and 3 variables (we should have the same number of equations than variables) then here is missing information, and we can't get an exact solution for the height of the flagpole.

But we can write it in terms of the height of the cliff H, or in terms of the distance between the observer and the cliff.

We want to find the value of h.

If we take the quotient between both equations, we get:

Tan(45°)/Tan(40°) = (H + h)/H

1.192 = (H + h)/H

1.192*H = H + h

1.192*H - H = h

0.192*H = h

So the height of the flagpole is 0.192 times the height of the cliff.

6 0
3 years ago
4. The revenue of a company for a given month is represented as ????(x) = 1,500x − x^2 and its costs as ????(x) = 1,500 + 1,000x
mrs_skeptik [129]

Answer:

The profit will be maximum on x = 250.

Step-by-step explanation:

From the given information:

Revenue = 1500x - x²

Cost = 1500 + 1000x

As we know that

Profit = Revenue - Cost ; Let say it equation 1

Then after putting the values of revenue and cost in equation 1 we have:

Profit = (1500x - x²) - (1500 + 1000x)

Profit = 1500x - x² - 1500 - 1000x

Profit = -x² + 500x - 1500

We know that at the max or min the slope of the graph formed by the profit function will be zero, therefore we find the slope of profit function by taking the first derrivative w.r.t. x as under:

d(Profit)/dx = d/dx(-x² + 500x - 1500)

d(Profit)/dx = -2x + 500

By putting the above slope equal to zero we get:

d(Profit)/dx = -2x + 500 = 0

-2x + 500 = 0

-2x = -500

x = 250

Therefore it is concluded that the profit will be maximum when x will be equal to 250.

4 0
4 years ago
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