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Snowcat [4.5K]
4 years ago
14

When he was little, Miguel could not sleep without his Captain Terrific action figure. It looked so life-like because it was a p

erfect scale model. The actor who plays Captain Terrific on television is 216 cm tall. Miguel’s doll is 10 cm tall. If the doll’s neck is 0.93 cm long, how long is the actor’s neck? Use the Undoing Division Method to solve this proportion: .
Mathematics
2 answers:
faust18 [17]4 years ago
7 0

The actor's neck is 20.08 cm long.

Step-by-step explanation:

The actor who plays Captain Terrific on television is 216 cm tall. Miguel’s doll is 10 cm tall.

Miguel’s doll is 10 cm tall and the doll’s neck is 0.93 cm long.

Let the doll's actor's neck be x cm

We can relate these as follows:

\frac{216}{x} =\frac{10}{0.93}

Solving for x now;

10x=216*0.93

=> 10x=200.88

x = 20.08

Hence, the actor's neck is 20.08 cm long.

krok68 [10]4 years ago
5 0
The answer is:
216×0.93÷10=20.088
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Answer:

a)

P(X = 0) = h(0,100,15,5) = \frac{C_{5,0}*C_{95,15}}{C_{100,15}} = 0.4357

P(X = 1) = h(1,100,15,5) = \frac{C_{5,1}*C_{95,14}}{C_{100,15}} = 0.4034

P(X = 2) = h(2,100,15,5) = \frac{C_{5,2}*C_{95,13}}{C_{100,15}} = 0.1377

P(X = 3) = h(3,100,15,5) = \frac{C_{5,3}*C_{95,12}}{C_{100,15}} = 0.0216

P(X = 4) = h(4,100,15,5) = \frac{C_{5,4}*C_{95,11}}{C_{100,15}} = 0.0015

P(X = 5) = h(5,100,15,5) = \frac{C_{5,5}*C_{95,10}}{C_{100,15}} = 0.00004

b) 0.154% probability that there are at least 4 defective welders in the sample

Step-by-step explanation:

The welders are chosen without replacement, so the hypergeometric distribution is used.

The probability of x sucesses is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

100 welders, so N = 100

Sample of 15, so n = 15

In total, 5 defective, so k = 5

(a) Determine the PMF of the number of defective welders in your sample?

There are 5 defective, so this is P(X = 0) to P(X = 5). Then

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

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P(X = 3) = h(3,100,15,5) = \frac{C_{5,3}*C_{95,12}}{C_{100,15}} = 0.0216

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P(X = 5) = h(5,100,15,5) = \frac{C_{5,5}*C_{95,10}}{C_{100,15}} = 0.00004

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