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BARSIC [14]
2 years ago
5

5. The internal dimension of a tank are 14m, 8m and 5m. How much water can be

Mathematics
1 answer:
EleoNora [17]2 years ago
3 0

Answer:

560,000L

Step-by-step explanation:

Given data

L=14m

W=8m

H=5m

Volume= L*W*H

Volume= 14*8*5

Volume= 560 m^3

1m^3 = 1000L

560m^3 = x

cross multiply

x= 560*1000

x= 560,000L

Hence the volume is  560,000L

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bagirrra123 [75]
B. 8 is the answer.

Simplify to 2^4^(3/4) then 2^3 then that simplies to 8
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3 years ago
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How far apart in feet are Marcus and Joel. Please round your answer to the nearest tenth of a foot
Pavel [41]

Answer:

The distance between Marcus and Joel is approximately 127.3 feet.

Step-by-step explanation:

The distances between Jean to Joel, Jean to Marcus and Marcus to Joel form a right triangle where the distance from Marcus to Joel is the hypothenuse. We can measure the distance from Jean to Marcus and Jean to Joel by using the grid provided, since they're along the same axis. This is shown below:

d(Jean, Marcus) = Jean(x) - Marcus(x) = 100 - 10 = 90 feet

d(Jean, Joel) = Jean(y) - Joel(y) = 90 - 0 = 90 feet

We can apply the pythagora's theorem to find the distance between Marcus and Joel.

d(Marcus,Joel)² = d(Jean,Marcus)² + d(Jean,Joel)²

d(Marcus,Joel)² = (90)² + (90)²

d(Marcus,Joel)² = 2*(90)²

d(Marcus, Joel) = sqrt(2*(90)²) = 90*sqrt(2) = 127.279 feet

The distance between Marcus and Joel is approximately 127.3 feet.

8 0
3 years ago
The graph above represents the following polynomial function.
Korvikt [17]

Answer:

C. 0, -1, 3

Step-by-step explanation:

Note: There is no graph. I assume you mean "zeroes/roots" by "solutions".

x(x^2-2x-3)=0

/(x^2-2x-3)

x=0


x^2-2x-3 = x^2+x-3x-3 = x(x+1) + ( -3(x+1) = (x-3)(x+1)

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3 years ago
10 × (8 + 3) – 6 + [8 × (3 + 2)]​
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Answer:

The answer is 144 :)

8 0
3 years ago
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(6-3(cube root of 6)/(cube root of 9)
MatroZZZ [7]

For this case we must simplify the following expression:

\frac {6-3 \sqrt [3] {6}} {\sqrt [3] {9}}

Multiplying the numerator and denominator by(\sqrt [3] {9}) ^ 2

\frac {6-3 \sqrt [3] {6}} {\sqrt [3] {9}} * \frac {(\sqrt [3] {9}) ^ 2} {(\sqrt [3] { 9}) ^ 2} =

We rewrite:

\frac {\frac {6-3 \sqrt [3] {6}} * (\sqrt [3] {9}) ^ 2} {\sqrt [3] {9} * (\sqrt [3] {9 }) ^ 2} =

By properties of powers we have that:

a ^ m * a ^ n = a ^ {m + n}\\\frac {(6-3 \sqrt [3] {6}) * (\sqrt [3] {9}) ^ 2} {(\sqrt [3] {9}) ^ 3} =\\\frac {(6-3 \sqrt [3] {6}) * (\sqrt [3] {9}) ^ 2} {9} =

We rewrite, moving the exponent within the radical:

\frac {(6-3 \sqrt [3] {6}) * \sqrt [3] {9 ^ 2}} {9} =\\\frac {(6-3 \sqrt [3] {6}) * \sqrt [3] {81}} {9} =

We can rewrite3 * 3 ^ 3 = 81

\frac {(6-3 \sqrt [3] {6}) * \sqrt [3] {3 * 3 ^ 3}} {9} =

We simplify:

\frac {(6-3 \sqrt [3] {6}) * 3 \sqrt [3] {3}} {9} =

We apply distributive property:

\frac {18 \sqrt [3] {3} -9 \sqrt [3] {18}} {9} =

Simplifying we finally have:

2 \sqrt [3] {3} - \sqrt [3] {18}

Answer:

2 \sqrt [3] {3} - \sqrt [3] {18}

5 0
3 years ago
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