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3 years ago

9

Find the slope Y=5x+12

1 answer:

NikAS [45]3 years ago

6 0

Answer: The slope = 5.

Step-by-step explanation:

The equation of a line in the slope -intercept form is given by :-

$y=mx+c$

,where m= slope , c= y-intercept.

The slope of a line represents the rate of change of y with respect to x.

Given: Equation of line : Y= 5x+12

Here Slope (m)=5

Hence, the slope = 5.

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What is the hypotenuse of a right triangle?

Alex73 [517]

The hypotenuse^2 = leg1^2 + leg2^2
The hypotenuse is always the LONGEST side of any right triangle.
It is also the side that is opposite the right angle

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3 years ago

What is 2+2+2-2+87 plz tell me so u would get 100 points

DedPeter [7]

Answer:

The answer is 91.

Step-by-step explanation:

Since 2+2+2=6 and you subtract 2 that would now be 6-2, and that is 4.

87+4=91.

Simply 6-2=4

87+4=91

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3 years ago

(14÷2)+((18+5)+4<br>order of operations

Amanda [17]

33 is the answer to that question

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3 years ago

Let Q(x, y) be the predicate "If x < y then x2 < y2," with domain for both x and y being R, the set of all real numbers.

Levart [38]

Answer:

a) Q(-2,1) is false

b) Q(-5,2) is false

c)Q(3,8) is true

d)Q(9,10) is true

Step-by-step explanation:

Given data is $Q(x,y)$ is predicate that $x$ then $x^{2}$ . where $x,y$ are rational numbers.

a)

when $x=-2, y=1$

Here $-2$ that is $x$ satisfied. Then

$(-2)^{2}$

$4$ this is wrong. since $4>1$

That is $x^{2}$ $>y^{2}$ Thus $Q(x,y)$ $=Q(-2,1)$ is false.

b)

Assume $Q(x,y)=Q(-5,2)$ .

That is $x=-5, y=2$

Here $-5$ that is $x$ this condition is satisfied.

Then

$(-5)^{2}$

$25$ this is not true. since $25>4$ .

This is similar to the truth value of part (a).

Since in both $x$ satisfied and $x^{2} >y^{2}$ for both the points.

c)

if $Q(x,y)=Q(3,8)$ that is $x=3$ and $y=8$

Here $3$ this satisfies the condition $x$ .

Then $3^{2}$

$9$ This also satisfies the condition $x^{2}$ .

Hence $Q(3,8)$ exists and it is true.

d)

Assume $Q(x,y)=Q(9,10)$

Here $9$ satisfies the condition $x$

Then $9^{2}$

$81$ satisfies the condition $x^{2}$ .

Thus, $Q(9,10)$ point exists and it is true. This satisfies the same values as in part (c)

6 0

3 years ago

A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between 46.0 and 56.

barxatty [35]

Answer: 0.05

Step-by-step explanation:

Given : Interval for uniform distribution : [46.0 minutes, 56.0 minutes]

The probability density function will be :-

$f(x)=\dfrac{1}{56-46}=\dfrac{1}{10}=0.1\ \ , 46$

The probability that a given class period runs between 50.75 and 51.25 minutes is given by :-

$P(50.75$

Hence, the probability that a given class period runs between 50.75 and 51.25 minutes = 0.05

7 0

3 years ago