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Arte-miy333 [17]
4 years ago
8

Which of the following equations is equivalent to log(y) = 5.112

Mathematics
2 answers:
Alecsey [184]4 years ago
7 0

Answer: y=10^5.112

Step-by-step explanation:

A P E X

belka [17]4 years ago
3 0
We are given the following equation:

log(y)=5.112

When a log is written without a base it is understood that its base is 10. So we can also write the above equation as:

log_{10}(y)=5.112

In order to transform logarithmic equation to exponential equation we move the base of log to other side of the equation and place the values on the other side in its exponent. So the above equation becomes:

y= 10^{5.112}

Thus, option b gives the correct answer
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What is the value of the expression -78-a, when a= -29?
Lady bird [3.3K]
ANSWER:
-78-a
= -78-(-29)
= -78+29
= -49
3 0
3 years ago
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PLEASE HELP‼️‼️Drag the expression that is the most reasonable measurement for each object.
Afina-wow [57]

Answer:

<em>A. Length of a Tour Bus                       ↔     #2.      1.1 × 10¹ meters</em>

<em />

<em>B. Width of an apple                             ↔      #3.     4 × 10⁰ centimeters</em>

<em />

<em>C. Distance from Earth to a Satellite    ↔    #6.     8 × 10² kilometers</em>

<em />

<em>D. Thickness of a human hair               ↔     #5.      9 × 10¹ micrometers</em>

Explanation:

<u><em>A. Length of a tour bus.</em></u>

The length of a tour bus should be measured in meters. It sure is way less than 1 kilometer and way more than a few centimeters. It could be about some meters, more than 5 meters, may be between 10 meters and 15 meters.

The measurement in the box # 2. is 1.1 × 10¹ meters, which is equivalent to 1.1 × 10meters = 11 meters. Thus, this is a reasonable length.

<u><em>B. Width of an apple.</em></u>

The most appropiate unit to measure the width of an apple should be centimer. It certanly is shorter than 1 meter and bigger than 1 mm.

The width of an apple could be, more or less, around 8 centimeters. The only measurement in the boxes that is in that order is that in the box #3., 4 × 10⁰ centimeters, because 10⁰ = 1, so 4 × 10⁰ = 4 × 1 = 4centimeters.

<u><em>C. Distance from Earth to a Satellite</em></u>

The distance from Earth to a satellite should be measured in kilometers.

You can find in the internet that the distances of the satellites are between 700 kilometers and 36,000 kilometers.

The number in the box #1 is too big, in the order of ten trillions of kilometers, because one trillion is 10¹²; thus that is notreasonalbe (too big).

The number in the box #6 is  8 × 10² kilometers, which is equal to 8 × 100 = 800 kilometers.

Thus,  8 × 10² kilometers (box #6) is the most reasonable measurement for the distance from Earth to a Satellite

<u><em></em></u>

<u><em>D. Thickness of a human hair</em></u>

Of course, kilometers, meters, centimeters and even milimeters are units too big to measure the thickness of a human hair.

One micrometer is 10⁻⁶ meters or 10⁻³ milimeters.

In the internet you can find that diameter of the humar hairis in the range from 17 micrometers to 181 micrometers.

The measurement in the box #5. is 9 × 10¹ micrometers, which is equivalent to 9 × 10 = 90 micrometers.

Thus, 9 × 10¹ micrometers is the most reasonable measurement fot the thickness of a human hair.

7 0
3 years ago
)) Matt's bill for breakfast at a restaurant was $91. He left an 18% tip. What was the total
gladu [14]

Answer:

$107.38

Step-by-step explanation:

$91 (the price) multiplied by the percentage 18% (91 x 18 = 1630) (1638/100=16.38 [the tip})

$91 (th original price) + 15.38 (the tip) = $108.38 (final price)

4 0
3 years ago
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Solve the following system of equations using the elimination method.
liraira [26]

Answer: its A

Step-by-step explanation:

8 0
4 years ago
Express the terms of the following geometric sequence recursively.
BabaBlast [244]

Answer:

The most correct option for the recursive expression of the geometric sequence is;

4. t₁ = 7 and tₙ = 2·tₙ₋₁, for n > 2

Step-by-step explanation:

The general form for the nth term of a geometric sequence, aₙ is given as follows;

aₙ = a₁·r⁽ⁿ⁻¹⁾

Where;

a₁ = The first term

r = The common ratio

n = The number of terms

The given geometric sequence is 7, 14, 28, 56, 112

The common ratio, r = 14/7 = 25/14 = 56/58 = 112/56 = 2

r = 2

Let, 't₁', represent the first term of the geometric sequence

Therefore, the nth term of the geometric sequence is presented as follows;

tₙ = t₁·r⁽ⁿ⁻¹⁾ = t₁·2⁽ⁿ⁻¹⁾

tₙ =  t₁·2⁽ⁿ⁻¹⁾ = 2·t₁2⁽ⁿ⁻²⁾ = 2·tₙ₋₁

∴ tₙ = 2·tₙ₋₁, for n ≥ 2

Therefore, we have;

t₁ = 7 and tₙ = 2·tₙ₋₁, for n ≥ 2.

4 0
3 years ago
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