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Sladkaya [172]
3 years ago
6

Suppose that the cost of renting a snowmobile is 37.50 for 5 hours. What would be the cost of renting 2 snowmobiles for 5hours?

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
8 0
75 dollars for renting 2 snowmobiles for 5 hours.
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Vesnalui [34]
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Hays builds model sailboats as a hobby. the dimensions of the sailboats are given. what is the height, x, of the smaller sailboa
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7/8=x/12
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y=2x+4

Step-by-step explanation:

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4 years ago
An equation of a hyperbola is given.
siniylev [52]

Answer:

a)

The vertices are \left(3,\:0\right),\:\left(-3,\:0\right).

The foci are \left(3\sqrt{5},\:0\right),\:\left(-3\sqrt{5},\:0\right).

The asymptotes are y=2x,\:y=-2x.

b) The length of the transverse axis is 6.

c) See below.

Step-by-step explanation:

\frac{\left(x-h\right)^2}{a^2}-\frac{\left(y-k\right)^2}{b^2}=1 is the standard equation for a right-left facing hyperbola with center \left(h,\:k\right).

a)

The vertices\:\left(h+a,\:k\right),\:\left(h-a,\:k\right) are the two bending points of the hyperbola with center \:\left(h,\:k\right) and semi-axis a, b.

Therefore,

\frac{x^2}{9}-\frac{y^2}{36}=1, is a right-left Hyperbola with \:\left(h,\:k\right)=\left(0,\:0\right),\:a=3,\:b=6 and vertices \left(3,\:0\right),\:\left(-3,\:0\right).

For a right-left facing hyperbola, the Foci (focus points) are defined as \left(h+c,\:k\right),\:\left(h-c,\:k\right) where c=\sqrt{a^2+b^2} is the distance from the center \left(h,\:k\right) to a focus.

Therefore,

\frac{x^2}{9}-\frac{y^2}{36}=1, is a right-left Hyperbola with \:\left(h,\:k\right)=\left(0,\:0\right),\:a=3,\:b=6 c=\sqrt{3^2+6^2}= 3\sqrt{5} and foci \left(3\sqrt{5},\:0\right),\:\left(-3\sqrt{5},\:0\right)

The asymptotes are the lines the hyperbola tends to at \pm \infty. For right-left hyperbola the asymptotes are: y=\pm \frac{b}{a}\left(x-h\right)+k

Therefore,

\frac{x^2}{9}-\frac{y^2}{36}=1, is a right-left Hyperbola with \:\left(h,\:k\right)=\left(0,\:0\right),\:a=3,\:b=6 and asymptotes

y=\frac{6}{3}\left(x-0\right)+0,\:\quad \:y=-\frac{6}{3}\left(x-0\right)+0\\y=2x,\:\quad \:y=-2x

b) The length of the transverse axis is given by 2a. Therefore, the lenght is 6.

c) See below.

4 0
4 years ago
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