The magnitude of the final velocity of the cue ball is (B) 0.56m/s.
<h3>
What is Velocity</h3>
- The definition of velocity is a vector measurement of the rate and direction of motion.
- It is a moving body's speed and direction of motion.
How to calculate the magnitude of the final velocity?
The magnitude of the final velocity can be calculated by following the steps:
- The mass of the cue ball given is 0.4kg.
- The velocity of the cue ball given is +0.80m/s.
- The velocity of the striped ball before the collision is +0.38 m/s.
- The velocity of the striped ball after collision is +0.62m/s.
- We need to find the magnitude of the final velocity of the cue ball.
Assuming all pool balls have the same mass: 0.4kg
Let the final velocity of the cue ball be x.
Now, To find the final velocity:
- Mass of the cue ball × initial velocity of cue ball + Mass of striped ball + initial velocity of striped ball = mass of cue ball × final velocity + mass of striped ball × final velocity of the striped ball
- (0.40)×(0.80)+(0.4)(0.38) = (0.4)(x)+(0.4)(0.62)
- 0.32+0.152=0.4x+0.248
- 0.472=0.4x+0.248
- 0.472-0.248= 0.4x
- 0.224/0.4 =x
- x = 0.56m/s
Therefore, the magnitude of the final velocity of the cue ball is (B) 0.56m/s.
Know more about velocity here:
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The correct question is given below:
In a game of pool, a 0.4 kg cue ball is traveling at +0.80 m/s when it hits a slower striped ball moving at +0.38 m/s. After the collision, the striped ball moves off at +0.62 m/s. What is the magnitude of the final velocity of the cue ball? Assume all pool balls have the same mass.
A. 0.20 m/s
B. 0.56 m/s
C. 1.0 m/s
D. 1.8 m/s
To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.
jk=ac and j+k=b
The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...
2k^2-5k-18=0
2k^2+4k-9k-18=0
2k(k+2)-9(k+2)=0
(2k-9)(k+2)=0
so k=-2 and 9/2
k=(-2, 4.5)
Answer:
65 gallons per minute
Step-by-step explanation:
The total volume of the tank at any given time is given by the equation:
V(t) = 65t + 280
In order to find the rate of change of volume, we can simply differentiate this equation with respect to time. This will give us the rate of change of the volume or the rate at which water is being pumped into the tank.
Differentiating the above equation we get:
V'(t) = 65
So we can see that the rate at which water is being pumped into the tank is 65 gallons per minute
The correct answer is 70 MPH because when 50 and 70 are added together and divided by 2, you get 60.
Answer:
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Step-by-step explanation:
