Write the polynomial in standard form. Then name the polynomial based on its degree and number of terms.
2 answers:
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Answer:
On a coordinate plane, a line goes through (0, 3) and (2, 4) and another line goes through (0, 3) and (0.75, 0).
This answer almost coincide with option C. I suppose there was a mistype.
Step-by-step explanation:
The system of equations is formed by:
–x + 2y = 6
4x + y = 3
In the picture attached, the solution set is shown.
The first equation goes through (0, 3) and (2, 4), as can be checked by:
–(0) + 2(3) = 6
–(2) + 2(4) = 6
The second goes through (0, 3) and (0.75, 0), as can be checked by:
4(0) + (3) = 3
4(0.75) + (0) = 3
we know that
the standard form of the equation of the circle is
where
(h,k) is the center of the circle
r is the radius of the circle
In this problem we have
<u>Convert to standard form</u>
Group terms that contain the same variable, and move the constant to the opposite side of the equation
Complete the square twice. Remember to balance the equation by adding the same constants to each side.
Rewrite as perfect squares
the center of the circle is
the radius of the circle is
therefore
<u>the answer is</u>
the radius of the circle is