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Step2247 [10]
3 years ago
12

Ursula Works At A Print Shop. She Uses A Printer That Can Print 12 Pages Per Minute. Yesterday She Started Printing Flyers For A

n Order. Today At 8 A.M. She Continued Working On The Order, And By 9 A.M. She Had 420 Flyers For The Order Completed. If The Job Was For 1500 Pages, At What Time Was It Finished?
Mathematics
1 answer:
BigorU [14]3 years ago
8 0

Answer:

10:30 am.

Step-by-step explanation:

We have been given that Ursula uses a printer that can print 12 pages per minute.

Ursula started printing flyer for an order yesterday. Today at 8 am she continued working on the order, and by 9 a.m. she had 420 flyers for the order completed. The order was to print 1500 pages.

Let us find the number of pages left to print.

\text{Number of the pages left to print}=1500-420

\text{Number of the pages left to print}=1080

To find the time it will take to print 1080 pages we will divide number of pages left to print by number of pages printed per minute.

\text{Time it will take to print 1080 pages}=\frac{1080\text{pages}}{\frac{\text{12 pages}}{\text{minute}}}}

\text{Time it will take to print 1080 pages}=\frac{1080\text{pages}}{12}\times \frac{\text{minute}}{\text{page}}}

\text{Time it will take to print 1080 pages}=90\text{ minutes}

90 minutes will be 1.5 hours , so 1.5 hours after 9 am will be 10:30 am. Therefore, the job was finished at 10:30 am.

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18x8=144.

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What is the range of y= x + 2?
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A) all real numbers greater than or equal to 2

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Step-by-step explanation:

The variable in the radical <em>x </em>cannot be less than 0 as that wouldn’t be defined. So, the maximum that <em>x </em>can be is 0, and y=x+2. So, 0+2=2, and <em>y </em>is greater than or equal to 2.

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3 years ago
Solve the equation on the interval [0, 2pi): 12cos^2 x-9=0<br><br><br> What to do?
siniylev [52]

Answer:

\large\boxed{x=\dfrac{\pi}{6}\ \vee\ x=\dfrac{5\pi}{6}\ \vee\ x=\dfrac{7\pi}{6}\ \vee\ x=\dfrac{11\pi}{6}}

Step-by-step explanation:

12\cos^2x-9=0\qquad\text{add 9 to both sides}\\\\12\cos^2x=9\qquad\text{divide both sides by 12}\\\\\cos^2x=\dfrac{9}{12}\\\\\cos^2x=\dfrac{9:3}{12:3}\\\\\cos^2x=\dfrac{3}{4}\to\cos x=\pm\sqrt{\dfrac{3}{4}}\\\\\cos x=\pm\dfrac{\sqrt3}{2}\\\\\text{Look at the picture}\\\\x=\dfrac{\pi}{6}\ \vee\ x=\dfrac{5\pi}{6}\ \vee\ x=\dfrac{7\pi}{6}\ \vee\ x=\dfrac{11\pi}{6}

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3 years ago
Help me find the answer please!
Dmitry_Shevchenko [17]
The correct answer is 11
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3 years ago
Read 2 more answers
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