Answer:
328 feet
Step-by-step explanation:
From a boat ont he lake, the angle of elevation to the top of a cliff is 11° 50'. If the base of the cliff is 1568 feet from the boat, how high is the cliff (to the nearest foot)
Step 1
Note that
that 11°50' is just 11 degrees and 50 minutes
60 minutes = 1 degree,
thus 50 minutes = x degree
50/60 degrees
= 0.83°
Hence: 11°50' = 11.83°.
Step 2
We solve using Trigonometric function of tan
tan theta = Opposite/Adjacent
theta = 11.83°
Adjacent = 1568 feet
Opposite = Height of the cliff = x
tan 11.83° = x/1568
Cross Multiply
x = tan 11.83 × 1568
x = 328.429195 feet
Approximately = 328 feet
The height of the cliff is 328 feet
23 because if u add bothe of them up
<span>m=10x-x for x
first subtract x from 10x
m=9x
divide both sides by 9
m/9=x
x=m/9</span>
Answer:
Answer:
8
Step-by-step explanation:
x= centesimal angle (100 degrees in a
right angle)
y= sexagesimal angle (90 degrees in a
right angle)
=
x - y = 15
xx90/100 = y
xx9/10 = y
X - XX9/10 = 15
10x/10 - 9x/10 = 15
=
X/10 = 15
x= 150
y = 150x9/10 = 15x9 = 135
=
using centesimal system:
the sum of all external angles in a
polygon is 400 degrees (a full circle).
one external angle is the complement
of one internal angle to 200 degrees =
200-150=50 degrees.
to find the number of sides of the
polygon we need to find the number of
angles or corners. and that is how many
external angles fit into the full circle.
n = 400/50 = 8
=
the polygon has 8 sides
