Answer:
its equal to -47
Step-by-step explanation:
i know it
Given:
The rate of interest on three accounts are 7%, 8%, 9%.
She has twice as much money invested at 8% as she does in 7%.
She has three times as much at 9% as she has at 7%.
Total interest for the year is $150.
To find:
Amount invested on each rate.
Solution:
Let x be the amount invested at 7%. Then,
The amount invested at 8% = 2x
The amount invested at 9% = 3x
Total interest for the year is $150.

Multiply both sides by 100.


Divide both sides by 50.


The amount invested at 7% is
.
The amount invested at 8% is

The amount invested at 9% is

Therefore, the stockbroker invested $300 at 7%, $600 at 8%, and $900 at 9%.
Answer:
i dont know if this is right but im pretty sure its 5
Step-by-step explanation:
Answer:
an = 4/3n - 13/3.
Step-by-step explanation:
The first term is a1,
a24 = a1 + 23d
83/3 = a1 + 4/3* 23
a1 = 83/3 - 92/3
a1 = -9/3 = -3.
So the nth term an = -3 + 4/3(n - 1)
an = -3 + 4/3 n - 4/3
an = 4/3n - 13/3